You can use the equation P(1+(n/t))^(n) to find the amount after time (t), given the starting amount(P) and the number of times compounded (n)
Answer: B) F(x) = √x and G(x) = 3x + 2
<u>Step-by-step explanation:</u>
The composite function G(F(x)) is when you replace every x-value in the G(x) function with the F(x) function.
![A)\ G(3x+2) = \sqrt{3x+2}\\\\B)\ G(\sqrt{x})=3(\sqrt{x})+2\quad =3\sqrt{x}+2\\\\C)\ G(\sqrt{x}+2) = 3\quad \text{there are no x-values in the G(x) function to replace}\\\\D) G(3\sqrt{x})=2\quad \text{there are no x-values in the G(x) function to replace}](https://tex.z-dn.net/?f=A%29%5C%20G%283x%2B2%29%20%3D%20%5Csqrt%7B3x%2B2%7D%5C%5C%5C%5CB%29%5C%20G%28%5Csqrt%7Bx%7D%29%3D3%28%5Csqrt%7Bx%7D%29%2B2%5Cquad%20%3D3%5Csqrt%7Bx%7D%2B2%5C%5C%5C%5CC%29%5C%20G%28%5Csqrt%7Bx%7D%2B2%29%20%3D%203%5Cquad%20%5Ctext%7Bthere%20are%20no%20x-values%20in%20the%20G%28x%29%20function%20to%20replace%7D%5C%5C%5C%5CD%29%20G%283%5Csqrt%7Bx%7D%29%3D2%5Cquad%20%5Ctext%7Bthere%20are%20no%20x-values%20in%20the%20G%28x%29%20function%20to%20replace%7D)
The only one that matches G(F(x)) = 3√x + 2 is OPTION B
Answer:
om how can we do that show workings 15cm how can we show workings
Step-by-step explanation:
Multiply the 2 numbers by how long she spoke
All you have to do is combine like terms. 2c and (-c) are like terms (-5b) and (-b) are like terms and a is a term. So, 2c combined with (-c) is C. (-5b) and (-b) combined is (-6b). Since a doesnt need to be combined with anything, you leave it as it is so your answer will then be c - 6b + a (this is the answer assuming that there is a + in front of the a. If there is a - sign, then just change your +a to -a at the end