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zmey [24]
3 years ago
5

A pendulum with a period of 2.00000 s in one location (g = 9.80 m/s^{2} 2 ) is moved to a new location where the period is now 1

.99796 s. What is the acceleration due to gravity at its new location?
Business
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

Acceleration due to gravity at new location will be g=9.820022m/sec^2

Explanation:

We have given time period of pendulum T = 2 sec

Acceleration due to gravity g=9.8m/sec^2

Time period of pendulum is given by T_1=2\pi \sqrt{\frac{L}{g}}, here L is length and G is acceleration due to gravity

So 2=2\pi \sqrt{\frac{L}{9.8}}------eqn 1

In second case time period is 1.99796 sec

So 1.99196=2\pi \sqrt{\frac{L}{g}}--------eqn 2

Now dividing eqn 1 by eqn 2

\frac{2}{1.99796}=\sqrt{\frac{g}{9.8}}

\sqrt{\frac{g}{9.8}}=1.00102

Squaring both side

\frac{g}{9.8}=1.00204

g=9.820022m/sec^2

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