As we go from (-6,6) to (9,1), x increases by 15 and y decreases by 5. Thus, the slope of this line is m = rise / run = -5/15, or m = -1/3.
Point-slope form: y-6 = (-1/3)(x+6), using data from (-6,6).
Slope-intercept form: starting with y = mx + b, substit. -6 for x, 6 for y and -1/3 for m:
6 = (-1/3)(-6) + b, or
6 = 2 + b. Then b = 4, and the equation in slope-intercept form is
y = (-1/3)x + 4.
Answer:
y = -
x + 7
Step-by-step explanation:
Ambos puntos (3, 5) y (6, 3) están en esta línea.
8 times 4 and 8 divided by 2 i think
The answer is (1/2)xe^(2x) - (1/4)e^(2x) + C
Solution:
Since our given integrand is the product of the functions x and e^(2x), we can use the formula for integration by parts by choosing
u = x
dv/dx = e^(2x)
By differentiating u, we get
du/dx= 1
By integrating dv/dx= e^(2x), we have
v =∫e^(2x) dx = (1/2)e^(2x)
Then we substitute these values to the integration by parts formula:
∫ u(dv/dx) dx = uv −∫ v(du/dx) dx
∫ x e^(2x) dx = (x) (1/2)e^(2x) - ∫ ((1/2) e^(2x)) (1) dx
= (1/2)xe^(2x) - (1/2)∫[e^(2x)] dx
= (1/2)xe^(2x) - (1/2) (1/2)e^(2x) + C
where c is the constant of integration.
Therefore,
∫ x e^(2x) dx = (1/2)xe^(2x) - (1/4)e^(2x) + C
You need more information. How much is each sandwich? You could give that value a variable too. In that case p=price of sandwich so earnings=px
