Ask question

Ask question

All categories

2 years ago

7

Simplify the expression. Use the variables, numbers, and symbols that are shown. Drag them to the appropriate box in the polynom

ial. Use standard polynomial format. x(2x + 3) + (x - 3)(x - 4)

1 answer:

Scilla [17]2 years ago

5 0

3x^2+4x-12 is your final answer

You might be interested in

A scale on a map shows that 2 inches equals 25 miles. How many miles is represented by 1/4 inch on the map?

FinnZ [79.3K]

3.125

to get this answer you divide 25 by 2, then divide that by 4, which equals 3.125

good luck hope I helped:)

8 0

2 years ago

Please help with #6 need it very soon

gregori [183]

Answer:

If this is a proof then here is the answer.

Angle ABD is Congruent to Angle CBD = Given

Angle BDA is Congruent to Angle BDC = Given

Angle ABD is Congruent to Angle CBD = Definition of Angle Bisector

Line Segment BD is Congruent to Line Segment BD = Reflexive Property

Line Segment AB is Congruent to Linge Segment CB = Angle-Side-Angle or ASA

Step-by-step explanation:

Lucky for you, I just learned this also ;)

Since you are given your first two directions, put them down as GIVEN in the proof.

Next, Since ABD and CBD are congruent angles, you can assume that it is an angle bisector since angle bisectors always bisect equally.

Then, (This one is obvious), since Line Segment BD shares a side with itself, it is equal by the Reflexive Property (EX: AB is congruent to AB).

Finally, Since there is two angles with a congruent side in the middle, you can confirm that it is equal by Angle-Side-Angle.

Hope this helped!

5 0

3 years ago

2^3a^7 times 2a^3 NEEE HELP

hichkok12 [17]

Step-by-step explanation:

explain step by step on photo, double check just in case

6 0

3 years ago

What is the slope of the line that passes through the pair of points (1/3, -1) and ( -2, 9/2)

UkoKoshka [18]

Answer:

$\boxed{m = - \frac{33}{14} }$

.

Step-by-step explanation:

Use the form below

$\boxed{\boxed{m = \frac{y_2 - y_1}{x_2 - x_1} }}$

Where

$m$ is a slope
$(x_1,~y_1)$ and $(x_2,~y_2)$ are the point of the line

.

So, the slope is

$(\frac{1}{3} ,~ -1) \to x_1 = \frac{1}{3} ~and~y_1 = -1$

$(-2,~ \frac{9}{2} ) \to x_2 = -2~and~y_2 = \frac{9}{2}$

.

$m = \frac{\frac{9}{2} -(-1)}{-2-\frac{1}{3} }$

$m = \frac{\frac{11}{2} }{\frac{-7}{3} }$

$m = \frac{11}{2} \div (-\frac{7}{3} )$

$m = \frac{11}{2} \times (-\frac{3}{7} )$

$m = - \frac{33}{14}$

.

Happy to help:)

7 0

3 years ago

Read 2 more answers

Do you think the equations (x−1)(x+3)=17+x and (x−1)(x+3)+500=517+x should have the same solution set? Why?

oksano4ka [1.4K]

Answer:

Those two pair of equations have the same solution set.

Step-by-step explanation:

There are two equations

(x-1)(x+3)=17+x ..... (1) and

(x-1)(x+3)+500=517+x ...... (2)

We have to check the same solution set will be there for equations (1) and (2) or not.

Now, we are going to rearrange the equation (2).

(x-1)(x+3)+500=517+x

⇒ (x-1)(x+3)=517-500+x

⇒(x-1)(x+3)=17+x

This is the same equation as equation (1).

Therefore, there will be the same solution set for equations (1) and (2). (Answer)

There are two equations

(x-1)(x+3)=17+x ..... (3) and

3(x-1)(x+3)+500=51+3x ...... (4)

We have to check the same solution set will be there for equations (3) and (4) or not.

Now, we are going to rearrange the equation (4).

3(x-1)(x+3)+500=51+3x

⇒ 3(x-1)(x+3)=3(17+x)

⇒(x-1)(x+3)=17+x

This is the same equation as equation (3).

Therefore, there will be the same solution set for equations (3) and (4). (Answer)

7 0

2 years ago