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prisoha [69]
3 years ago
14

A number cubed is rolled. What is the probability that a one or six will be rolled

Mathematics
2 answers:
son4ous [18]3 years ago
6 0

Answer: 1/3

Step-by-step explanation: Since there are six sides to a number cube, the total number of outcomes will be 6.

Since there are 2 favorable outcomes, rolling a 1 or a 6,

the probability of rolling a 1 or a 6 is 2/6 which reduces to 1/3.

KatRina [158]3 years ago
4 0

Answer:

1/3

Step-by-step explanation:

A cube by default has 6 sides, and a number cube generally is tallied from 1 - 6 (being the numbers are 1, 2, 3, 4, 5, 6).

You are solving for the probability of the numbers 1 or 6 being rolled, which are 2 numbers of the given amount. Change into a fraction form by placing part over the total amount of numbers:

2/6

Most likely, you will be told to simplify. Divide common factors from both the numerator & denominator:

(2/6)/(2/2) = 1/3

1/3 is the probability that a 1 or a 6 is rolled in a standard number cube.

~

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Opposite sides are equal in length and opposite angles are equal in measure. To find the area of a parallelogram, multiply the base by the height. The formula is: A = B * H where B is the base, H is the height, and * means multiply.

Step-by-step explanation:

7 0
2 years ago
Use a number line to add 5/2 and the additive inverse of 0.4
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If the measure of angle 2 is 125 degrees, find the measure of angle 3.PLS HELP
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12/x=4/3 help me what do x =
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x=9

Step-by-step explanation:

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Read 2 more answers
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
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