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ohaa [14]
2 years ago
6

2 Ella, James, and Ray's grandmother gave them $24 to divide equally. They spent the

Mathematics
1 answer:
Musya8 [376]2 years ago
3 0

3 kids and $24 will give each 24/3=$8 each

$8 for 4days is 8/4=$2 a day they spent

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Solving for x<br><br> r + 11 + 8r = 29
NikAS [45]

Answer:

r=2

Step-by-step explanation:

r + 11 + 8r = 29

add the like terms

r+8r+11=29

9r+11=29

then subtract 11 on both sides to eltimate 11

9r=18

lastly divide 9 on both sides

r=2

7 0
2 years ago
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Critical points of x+5/x+2&gt;0
Scorpion4ik [409]

Answer:

{-5, -2}

Step-by-step explanation:

In a case like this please use parentheses to remove ambiguities.  If I were to take your "x+5/x+2" literally, I'd have to write x             plus 5/x           plus 2.

I suspect that you actually meant (x + 5) / (x + 2), and will start with that.

First of all, this function is not defined at x = -5 or at x = -2.  Thus, -5 and -2 are critical points.  

Secondly, there may be one or more critical points beyond this.  To find out, we have to differentiate (x+5)/(x+2):

           (x + 2)(1) - (x + 5)(1)

f '(x) = ------------------------------

                  (x + 2)

Here it's clear that x cannot = -2, which would cause division by zero.

Thus, our critical values are {-5, -2}.

8 0
3 years ago
Solve 5(2x – 3) = x – 15 + 9x for x.
Alexxandr [17]

Answer:

the correct answer is option C) 0

Hope that helps! :)

4 0
2 years ago
The sizes of the interior angles of a triangle are in the ratio 1:3:8
dangina [55]

Answer:

3:9:24

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Select all the expressions that are equivalent to (2)^n+³
eimsori [14]

Answer:

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

  • a^{m} × a^{m}  = a^{m+n}
  • (a^{m})^{n} = a^{m*n}

Now let us find the equivalent expressions of  (2)^{n+3}

A.

∵ 4 = 2 × 2

∴ 4 =  2^{2}

∴  (4)^{n+2} =  (2^{2})^{n+2}

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴  (4)^{n+2} =  (2)^{2n+4}  

B.

∵ 4 = 2 × 2

∴ 4 =  2²

∴  4(2)^{n+1} = 2² ×  (2)^{n+1}

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴   4(2)^{n+1} =  (2)^{n+3}

C.

∵ 8 = 2 × 2 × 2

∴ 8 =  2³

∴  8(2)^{n} = 2³ ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴  8(2)^{n} =  (2)^{n+3}

D.

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = 2^{4}

∴  16(2)^{n} = 2^{4}  ×  (2)^{n}

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴  16(2)^{n} =  (2)^{n+4}

E.

(2)^{2n+3} is in its simplest form

The expressions which equivalent to  (2)^{n+3} are:

4(2)^{n+1}  ⇒ B

8(2)^{n} ⇒ C

3 0
3 years ago
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