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bogdanovich [222]
3 years ago
6

According to the kinetic theory, what is the kinetic energy of a gas molecule proportional to?

Chemistry
1 answer:
n200080 [17]3 years ago
6 0
It is directly proportional to absolute temperature only.
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3 0
3 years ago
Is garlic powder a pure substance
CaHeK987 [17]

Answer: most store-bought isnt

Explanation:

there typically a lot of addivitves

8 0
3 years ago
How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?
Finger [1]

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

3 0
3 years ago
What volume of a 0.2089 M KI solution contains enough KI to react exactly with the Cu(NO3)2 in 40.88 mL of a 0.3842 M solution o
tatyana61 [14]

Explanation:

As molarity is the number of moles placed in a liter of solution. Therefore, no. of mole = Molarity × volume of solution in liter

Hence, moles of Cu(NO_{3})_{2} will be calculated as follows.

No. of mole of Cu(NO_{3})_{2} = 0.3842 M \times 0.04388 L = 0.0168 mole

According to the given reaction, 2 mole of Cu(NO_{3})_{2} react with 4 mole of KI.

Therefore, for 0.0168 mole amount of Cu(NO_{3})_{2} required will be as follows.

Cu(NO_{3})_{2} = 0.0168 \times \frac{4}{2}

                       = 0.0337 mole of KI

Hence, volume of KI required will be calculated as follows.

               Volume = \frac{\text{no. of moles}}{Molarity}

    Volume of KI = \frac{0.0337}{0.2089}

                           = 0.1614 liter

                            = 161.4 ml            (as 1 L = 1000 mL)

Thus, we can conclude that 161.4 ml  volume of a 0.2089 M KI is required for the given situation.

5 0
3 years ago
The main group elements do not include which elements?
kaheart [24]

Answer:

Transition metals

Explanation:

Columns one and two are part of the main group along with columns 13 through 18

8 0
3 years ago
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