Answer:
Explanation:
For the reaction 
C2H5OH (l) + 3 O2(g) = 2CO2(g) + 3 H2O
We can calculate the  standard molar enthalpy of combustion using the standard enthalpies of formation of the species involved in the reaction according to Hess law:
ΔHºc =  2ΔHºf CO2 (g) + 3ΔHºfH2O(l)  - ( ΔHºf C2H5OH (l) - 3ΔHºfO2 (g) )
( we were not give the water state but we know we are at standard conditions so it is in its liquid state ) 
The ΔHºfs can be found in appropiate reference or texts.
ΔHºc =  2ΔHºf CO2 (g)+ 3ΔHºfH2O(l)  - (  ΔHºf C2H5OH (l) -+3ΔHºfO2 (g) ) 
= [ 2 ( -393.52 ) + 3 ( -285.83 ) ] - [(  -276.2 + 0 ) ] kJ
ΔHºc =  -1368.33 kJ
 
        
             
        
        
        
No it is not
hope  this helped
        
                    
             
        
        
        
 Answer:
-Atoms are neutral; they contain the same number of protons as electrons. By definition, an ion is an electrically charged particle produced by either removing electrons from a neutral atom to give a positive ion or adding electrons to a neutral atom to give a negative ion.
-An atom has an equal number of protons and electrons. An ion has an imbalance between the number of protons and electrons.
-An atom has no electrical charge. Ions have an electrical charge because they have an imbalance of protons and electrons.
Explanation:
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K2Cr2O7 + 14HCl → 2CrCl3 + 2KCl + 3Cl2 + 7H2O 
the correct option is :
K2Cr2O7, because the oxidation number of Cr changes from +6 to +3.
<u>Oxidation number of Cr in K2Cr2O7 is:</u>
K2Cr2O7 = 2K + 2 Cr + 7 O
 = 2(+1) + 2Cr + 7(-2) 
= 2 + 2Cr -14 
[total charge on K2Cr2O7 = 0], Hence;
2 + 2Cr -14 = 0
2Cr -12 = 0
2Cr = 12
Cr = 12/2
<u>Cr = +6</u>
<u>Oxidation number of Cr in CrCl3 is:</u>
CrCl3 = Cr + 3Cl = 0
 Cr + 3(-1) = 0
Cr -3 = 0
<u>Cr = +3</u>
Hence Cr is changing its oxidation number from 
+6 in K2Cr2O7 to +3 in CrCl3.
Since the oxidation number of Cr [ +6 → +3] is decreasing here,
Cr is getting reduced.
   
so K2Cr2O7 is an oxidizing agent,as it is getting itself reduced and oxidizes others.