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Rashid [163]
4 years ago
7

In part 2 of the experiment, you will be analyzing a sample of household bleach. A 0.0854 g sample of household bleach is comple

tely reacted with KI(s). The resulting solution is then titrated with 0.150 M NaS2O3 solution. 0.890 mL of the solution is required to reach the colorless endpoint. What is the mass percent of NaOCl (MM = 74.44 g/mole) in the bleach? a. 30.1% b. 96.5% c. 2.23% d. 5.82%
Chemistry
1 answer:
marysya [2.9K]4 years ago
4 0

Answer:

The correct answer is option d.

Explanation:

NaClO(aq)+2KI(s)+H_2O(l)\rightarrow NaCl(aq)+I_2(aq)+2KOH(aq)..[1]

I_2(aq)+2Na_2S_2O_3(aq)\rightarrow 2NaI(aq)+Na_2S_4O_6(aq)..[2]

moles of sodium thiosulfate solution = n

Molarity of the sodium thiosulfate solution = 0.150 M

Volume of sodium thiosulfate solution used = 0.890 mL = 0.00089 L

n=Molarity\times Volume (L)

n=0.150 M\times 0.00089 L=0.0001335 mol

According to reaction [2], 2 moles of sodium thiosulfate reacts with 1 mol I_2.

Then , 0.0001335 mol of sodium thiosulfate will reacts with:

\frac{1}{2}\times 0.0001335 mol=0.00006675 mol of I_2

Moles of I_2 = 0.00006675 mol

According to reaction [1], 1 mol of I_2 is obatnied from 1 mol of NaClO.

Then 0.00006675 mol of I_2 will be obtained from:

\frac{1}{1}\times 0.00006675 mol=0.00006675 mol

Mass of 0.00006675 mol of NaClO=

0.00006675 mol × 74.44 g/mol = 0.00496887 g

Mass of sample = 0.0854 g

Percentage of NaClO in sample:

\frac{0.00496887 g}{0.0854 g}\times 100=5.82\%

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7nadin3 [17]

What is pollen in the reproduction cycle of flowering plants?

A pollen grain is a microspore containing the male gametophyte, usually reduced to two undivided cells, each with one haploid (n) nucleus. These cells are surrounded by a very resistant wall, the exine, which generally has apertures, zones with less resistance which will allow the germination of the pollen tube.

Explanation of the reproduction cycle (cf diagram above)

A given species produces flowers bearing stamens. According to species, these flowers can be unisexual (stamens only) or bisexual (stamens and carpels).

The stamen anthers include 4 pollen sacs containing sporogenous cells (diploid=2n). These sporogenous cells undergo meiosis, each producing 4 microspores (haploid=n). Two nuclei are then formed by mitosis : the vegetative nucleus and the generative nucleus. The latter divides to form 2 sperms. Simultaneously the wall of the microspores becomes thicker and takes the characteristic shape of the species : it is a pollen grain (see: What are the morphological characteristics of pollen and spore grains?). In the majority of species, the 4 grains (resulting from the 4 microspores) split up into single grains; in some cases, they remain together (tetrad = group of 4 grains). When mature, pollen grains are released by the opening of the anthers.

A pollen grain is aimed at reaching another flower of the same species, bearing carpels. The ovaries contain ovules, in which meiosis occurs, then mitoses. It results in an embryo sac with 8 nuclei, among which an egg cell and 2 central cells. When a pollen grain arrives on another flower (see : How are the spores and pollen grains transported?), it is received by the stigmas.

The pollen grain germinates through an opening of the wall: the vegetative nucleus develops into a pollen tube which is guided by the style to the ovary, then enters the micropyle of an ovule. The pollen tube releases 2 sperm nuclei into the ovule: one of the sperms fuses with the egg cell into a zygote (2n), while the other sperm fuses with central nuclei and gives rise to albumen (= food source). There are generally several ovules in an ovary : each one can be fertilized by a distinct pollen grain.

Each fertilized ovule and its albumen form a seed that will develop into a new individual of this species. hope it works

4 0
3 years ago
Read 2 more answers
0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?
ioda

Answer:

V₂ =  1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ =  1.92 L

4 0
3 years ago
C12H22O11 + 11 H2SO4 → 12 C + 11 H2SO4 + 11 H2O
BlackZzzverrR [31]
Answer:
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Explanation:
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5 0
3 years ago
Please help me with my "Math Skills" thanks
AURORKA [14]
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7 0
3 years ago
A solution is made by dissolving 10.7 g of magnesium sulfate, MgSO4, in enough water to make exactly 100 mL of solution. Calcula
adell [148]

Answer:

[MgSO₄] = 890 mM/L

Explanation:

In order to determine molarity we need to determine the moles of solute that are in 1L of solution.

Solute: MgSO₄ (10.7 g)

Solvent: water

Solution: 100 mL as volume. (100 mL . 1L / 1000mL) = 0.1L

We convert the solute's mass  to moles → 10.7 g / 120.36 g/mol = 0.089 moles

Molarity (mol/L) → 0.089 mol/0.1L = 0.89 M

In order to calculate M to mM/L, we make this conversion:

0.89 mol . 1000 mmoles/ 1 mol = 890 mmoles

4 0
3 years ago
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