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Alexxx [7]
2 years ago
13

How many moles of carbon dioxide gas should be produced when 10.0 g of C2H6 are combusted at STP?

Chemistry
1 answer:
Finger [1]2 years ago
3 0

Answer:

                    0.665 moles of CO₂

Explanation:

                     The balance chemical equation for the combustion of Ethane is as follow:

                            2 C₂H₆ + 7 O₂ → 4 CO₂ + 6 H₂O

Step 1: <u>Calculate moles of C₂H₆ as;</u>

                              Moles  =  Mass  /  M.Mass

Putting values,

                              Moles  =  10.0 g / 30.07 g/mol

                              Moles  =  0.3325 moles

Step 2: <u>Calculate Moles of CO₂ as;</u>

According to balance chemical equation,

                    2 moles of C₂H₆ produced  =  4 moles of CO₂

So,

             0.3325 moles of C₂H₆ will produce  =  X moles of CO₂

Solving for X,

                      X  =  0.3325 mol × 4 mol ÷ 2 mol

                      X = 0.665 moles of CO₂

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how many grams of calcium oxide are producer from the decomposition of 125 grams of calcium carbonate
Dmitrij [34]

70.0 g. The decomposition of 125 g CaCO3 produces 700 g CaO.

MM = 100.09 56.08

CaCO3 → CaO + CO2

Mass 125 g

a) Moles of CaCO3 = 125 g CaCO3 x (1 mol CaCO3/100.09 g CaCO3)

= 1.249 mol CaCO3

b) Moles of CaO = 1.249 mol CaCO3 x (1 mol CaO/1 mol CaCO3)

= 1.249 mol CaO

c) Mass of CaO = 1.249 mol CaO x (56.08 g CaO/1 mol CaO) = 70.0 g

7 0
3 years ago
What is the density of an object that has a mass of 62.4grams and a volume of7.6cm^3?
Monica [59]

Answer:

<h3>The answer is 8.2 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 62.4 g

volume = 7.6 cm³

We have

density =  \frac{62.4}{7.6}  \\  = 8.2105263157...

We have the final answer as

<h3>8.2 g/cm³</h3>

Hope this helps you

5 0
3 years ago
What did henry mosely do?, What did he discover and how it proved that mendeleev's period was valid?
Anettt [7]
Henry Mosely reorganized Mendeleev's periodic table so it would be in order of atomic number (number of protons) instead of in order by atomic mass. (I don't know the answer to the other 2 questions I apologize)
8 0
3 years ago
Work = Force X Distance A dog pulls a ball with 5N of force for 4 m. How
Evgesh-ka [11]

Answer:

W = 20 J

Explanation:

Given that,

The force acting on the dog, F = 5 N

Distance covered, d = 4 m

We need to find the work done by the dog. The work done by an object is given by :

W = Fd

Put all the values,

W = 5 N × 4 m

W = 20 J

So, 20 J of work is done by the dog.

7 0
2 years ago
If the rate of formation of ammonia gas in haber bosch 2.5x10-4 mol/l-1/s-1 then rate of consumption of n2 gas during process eq
Doss [256]

Rate of  consumption of  N₂ = - 1.25 x 10⁻⁴

<h3>Further explanation </h3>

The reaction rate (v) shows the change in the concentration per unit time.  

\tt rate=\dfrac{concentration(M)}{time(s)}

The rate reaction for Haber Bosch :

N₂(g)+3H₂(g)⇒2NH₃(g)

From equation, mol ratio N₂ : NH₃ = 1 : 2, so<em> </em>

<em>the rate of formation of ammonia = 2 x the rate of consumption of nitrogen.</em>

Given

the rate of formation of ammonia gas : 2.5x10⁻⁴ M/s

the rate of consumption of nitrogen :

\tt \dfrac{2.5\times 10^{-4}}{2}=1.25\times 10^{-4}

The sign negative for consumption : -1.25 x 10⁻⁴ M/s

or we can use another way:

Rate of formation of  NH₃  = reaction rate x coefficient of  NH₃

2.5 x 10⁻⁴ = reaction rate x 2

reaction rate = 1.25 x 10⁻⁴

Rate of  consumption of  N₂  = reaction rate x coefficient of N₂

Rate of  consumption of  N₂ =  1.25 x 10⁻⁴ x 1

Rate of  consumption of  N₂ =  1.25 x 10⁻⁴

<em />

6 0
2 years ago
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