x = 10.22 in
Solution:
Width of the figure = x in
Length of the figure = (2x + 5) in
Area of the figure = 260 in²
<u>To find the value of x:</u>
<em>Area of the figure = length × width</em>
length × width = 260
(2x + 5) × x = 260
Subtract 260 from both sides of the equation.
Factor the above quadratic expression.
Quadratic equation formula:
x = 10.22, x = –12.72006
Dimension of the figure cannot be measured in negative terms.
Hence x = 10.22 in.
Answer:
the answer is C.
Step-by-step explanation:
equals to 125
Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation
√(4x+41)=x+5
1) x=2, √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8, √(4*(-8)+41)=-8+5, √9 =-3 false,
so an extraneous solution x=-8
So what you are trying to find is the certain amount of children tickets and adult tickets. the final amount is a total of $12. This means that a unknown number of children tickets (c) times 1.50 (price of each ticket for children) plus the unknown number of adult tickets (a) times 4.00 (price of each ticket for adults) equals a final cost of $12.00.
Equation: 1.50c+4.00a= 12.00
