It says that the value of a box above two boxes is found by adding the expressions in the two boxes. I filled in the boxes. The top box is 13x + 30, or option B.
A local high school held a two-day fundraiser selling lunches. The equations shown represent the amount of money the school coll
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Volume of a cone: 1/3
r²h
r is the radius (diameter ÷ 2) and h is the height.
Find the radius first using the diameter: 2
÷ 2 = 1.25
Now plug in the numbers into the formula.
1/31.25²10 = <span>16.4
</span>
The volume of the cone is 16.4 cubic feet.
r is the radius (diameter ÷ 2) and h is the height.
Find the radius first using the diameter: 2
Now plug in the numbers into the formula.
1/3
</span>
The volume of the cone is 16.4 cubic feet.
The diet will include <u>123.75 </u>daily grams of protein
<h3>Further explanation</h3>One variable linear equation is an equation that has a variable and the exponent number is one.
Can be stated in the form:
or
ax + b = c, where a, b, and c are constants, x is a variable
We complete the task :
A nutritionist planning a diet for a football player wants him to consume 3,500 Calories and 725 grams of food daily. Calories from fat and protein will be 45% of the total Calories. There are 4, 4, and 9 Calories per gram for protein, carbohydrates, and fat, respectively. How many daily grams of protein will the diet include?
- 243.75
- 481.25
- 123.75
- 120
Calories from fat and protein will be 45% (0.45) of the total Calories
Calories from fat and protein = 0.45 x 3500 = 1575 calories
Calories from carbohydrates = 3500 - 1575 = 1925 calories
So mass for carbohydrates = 1925 : 4(4 calories/gram) = 481.25 grams
Then mass for fat and protein = 725 - 481.25 = 243.75 grams
We can make equation for fat and protein
1. 4 calories. mass of protein(p) + 9 calories . mass of fat(f) = 1575 calories
2. mass of protein(p) + mass of fat(f) = 243.75
we can simplify :
1. 4p+9f = 1575
2. p + f = 243.75 ⇒ f = 243.75 - p
we substitute equation 2 into equation 1 :
4p + 9(243.75-p) = 1575
4p + 2193.75-9p=1575
-5p = -618.75
p = 123.75
<h3>Learn more</h3>
linear equation
Keywords : one variable, linear equation ,diet, nutritionist,calories, fat, proteins, carbohydrates, daily grams
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The larger of the two roots of the equation would be 28.59.
Suppose that the given quadratic equation is
Then its roots are given as:
The given quadratic equation is
now, the roots of the equation are
The two roots are 0.27 and 28.59.
Thus, the larger of the two roots of the equation would be 28.59.
Learn more about finding the solutions of a quadratic equation here:
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