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Ugo [173]
3 years ago
8

a bag is filled with blue and green marbles. there are three rimes as many blues as green ones. if the bag contains 280 marbles

total. how many blue ones are there?
Mathematics
2 answers:
Anna11 [10]3 years ago
6 0
There are 210 blue marbles! 
zepelin [54]3 years ago
6 0
Let b represent blue marbles
g represent green marbles
Then,
We know that there are three times as many blues as green ones, so
b=3g
Next,
the bag contains 280 marbles total, so:
b+g=280 marbles
Substitute b=3g into this equation, to get
3g+g=280 marbles
4g=280 marbles
Divided 4 to each side
4g/4=280/4
g=70 marbles
b=3r
b=3(70)
b=210 marbles
Check:
b=3r
210=3(70)
210=210
b+g=280
210+70=280
280=280. As a result, there area 210 blue marbles. Hope it help!
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Answer:

Measure of major arc BDC = 260.5°       Option A

Step-by-step explanation:

Given that, measure of central angle ∠BAE = 80.5°

Firstly we will find the measure of arc BE .  

The measure of arc BE  is same as the measure of its central angle.

So, measure of minor BE arc = 80.5°

measure of arc EDC = 180°  because of half circle

So,

measure of major arc BDC = 180° + 80.5° = 260.5°       option A

That's the final answer.

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Find the area and the perimeter of the shaded regions below. Give your answer as a completely simplified exact value in terms of
Finger [1]

Answer:

Area of shaded part = 41.09733550

Perimeter of shaded part = 35.82011867

Step-by-step explanation:

Area of shaded part =  ((πr^2)   4) - (bh ÷ 2)

Area of shaded part = ((π(12)^2) ÷ 4) - ((12)(12) ÷ 2)

Area of shaded part = (452.3893421 ÷ 4) - (144 ÷ 2)

Area of shaded part = (113.0973355) - (72)

Area of shaded part = 41.09733550

Perimeter of shadedpart:

AC = √a^2 + b^2

AC = √12^2 + 12^2

AC = √144 + 144

AC = √288

AC = 16.97056275

Perimeter of whole circle ÷ 4:

C=2πr

C=2π(12)

C=75.39822369

C ÷ 4 = 75.39822369 ÷ 4

C ÷ 4 = 18.84955592

<em>Perimeter of shaded part: </em>

18.84955592 + 16.97056275 = 35.82011867

7 0
4 years ago
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