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Arada [10]
3 years ago
7

What is the answer for this problem 6x+3=5x

Mathematics
1 answer:
liberstina [14]3 years ago
5 0
Okay so the first thing you need to do is move the all the variables to one side of the equal sign

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A theatre holds 1200 people when full.If it is 80% full,how many people are present
CaHeK987 [17]

0.8 times 1200 is 960, which is the number of people when the theatre is 80% full.

4 0
3 years ago
What is the reciprocal of 2/7​
sineoko [7]

Answer:

the reciprocal of 2/7 is 7/2. you just switch the numbers

4 0
3 years ago
Simplify the following expression:<br> 3X(4-1) + (6+21)
Ilya [14]

Answer:

9x+27

Step-by-step explanation:

3x(4−1)+6+21

=9x+6+21

Combine Like Terms

=9x+6+21

=(9x)+(6+21)

=9x+27

3 0
3 years ago
Read 2 more answers
Arian is making bracelets. For each bracelet, it takes 1/10 of hour to pick out materials and 1/4 hour to braid it together. How
-Dominant- [34]
Change everything into 10ths as follows:

1/10 + 2.5/10 = 3.5/10 of an hour to make one bracelet. Then change to 20ths so the numerator is a whole number.
Divide your time available by the time it takes to make one.

21
4 = 420= 15 bracelets
7 28
20

(as a whole number there was no fraction or remainder to round off)
7 0
3 years ago
I need answer Immediately pls!!!!!!
Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

n(U)=27

n(A)=7

n(B)=18

n(A'\cap B')=7

We know that,

n(A\cup B)=n(U)-n(A'\cap B')

n(A\cup B)=27-7

n(A\cup B)=20

Now,

n(A\cup B)=n(A)+n(B)-n(A\cap B)

20=7+18-n(A\cap B)

n(A\cap B)=7+18-20

n(A\cap B)=25-20

n(A\cap B)=5

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}

\text{Probability}=\dfrac{5}{27}

Therefore, the required probability is \dfrac{5}{27}.

3 0
3 years ago
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