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3 years ago

What is the answer for this problem 6x+3=5x

Mathematics

1 answer:

liberstina [14]3 years ago

5 0

Okay so the first thing you need to do is move the all the variables to one side of the equal sign

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If f(x)=2(x)^2+5\sqrt((x+2)), complete the following statement f(0)=

DENIUS [597]

Answer: 5

Step-by-step explanation:

$f(x)=2(x)^2+5\\\\f(0)=2(0)^2+5\\\\.\qquad =0+5\\\\.\qquad =5$

3 0

3 years ago

A= 47 sq. in. Find the value of x. If necessary, round to the nearest tenth.

motikmotik

Answer:

x = 9.7

Step-by-step explanation:

The area of a triangle is A = b * h / 2 where A, b, and h are the area, base and height respectively. We know that A, b, and h equal 47, x, and x respectively so we can write:

47 = x * x / 2

47 = x² / 2

94 = x²

x = ±√94

In context, x can't be negative so the answer is x = √94 = 9.7.

3 0

3 years ago

Read 2 more answers

Answer to cheek your knowledge

scZoUnD [109]

Answer:

D - ASA

This should be the answer since FH and IG can be said to be parallel and therefore we can find both alternate angles or a vertical opposite angle with one side given. We know that ΔFHJ is reduced by a factor of 2 to get ΔGIJ.

7 0

2 years ago

(8x + 9) + (15 - 8x)

Ilia_Sergeevich [38]

8x +9 + 15-8x is -32 it’s that easy

5 0

3 years ago

How far apart in feet are Marcus and Joel. Please round your answer to the nearest tenth of a foot

Pavel [41]

Answer:

The distance between Marcus and Joel is approximately 127.3 feet.

Step-by-step explanation:

The distances between Jean to Joel, Jean to Marcus and Marcus to Joel form a right triangle where the distance from Marcus to Joel is the hypothenuse. We can measure the distance from Jean to Marcus and Jean to Joel by using the grid provided, since they're along the same axis. This is shown below:

d(Jean, Marcus) = Jean(x) - Marcus(x) = 100 - 10 = 90 feet

d(Jean, Joel) = Jean(y) - Joel(y) = 90 - 0 = 90 feet

We can apply the pythagora's theorem to find the distance between Marcus and Joel.

d(Marcus,Joel)² = d(Jean,Marcus)² + d(Jean,Joel)²

d(Marcus,Joel)² = (90)² + (90)²

d(Marcus,Joel)² = 2*(90)²

d(Marcus, Joel) = sqrt(2*(90)²) = 90*sqrt(2) = 127.279 feet

The distance between Marcus and Joel is approximately 127.3 feet.

8 0

3 years ago