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slamgirl [31]
3 years ago
12

I need so much help!! please. i'm literally failing math

Mathematics
2 answers:
Tems11 [23]3 years ago
8 0
V = 3.14 x 12 x 3.4 x 3.4
V = 435.6.1 ft^2

hope it helps
11111nata11111 [884]3 years ago
4 0
Yeah thats probubly it

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The ___ of a parabola is the line, along with a point not on the line, which is used to generate a parabola.
enot [183]

Answer:

Directrix

Step-by-step explanation:

The <u>directrix</u> of a parabola is the line, along with a point not on the line (which is the <em>focus</em>), which is used to generate a parabola.  The <em>directrix</em> is parallel either to the x- or y-axis, and is perpedicular to the parabola's axis of symmetry (at x = h).      

Therefore, the correct answer is "<u>directrix</u>."  

3 0
3 years ago
Taylor ran 2 1/4 miles and walked 2 4/5 miles. How far did she run and walk
irinina [24]
Okay. So, we should convert fractions to the least common denominator, which is 20. That would be 2 5/20 and 2 16/20. Add both of those numbers up to get 5 1/20. Taylor ran and walked 5 1/20 miles.
5 0
3 years ago
Helpp meee please!!!! asap​
Vladimir [108]
A. x-6=6

if u plug in 12, you get 12-6=6 which is true
all the other ones would be false if you plugged in 12
3 0
3 years ago
Classify ABC by its sides. Then determine whether it is a right triangle.
m_a_m_a [10]

Answer:

∴Given Δ ABC is not a right-angle triangle

a= AB = √45 = 3√5

b = BC = 12

c = AC = √45 = 3√5

Step-by-step explanation:

Given vertices are A(3,3) and B(6,9)

            AB = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

            AB = \sqrt{(9-3)^{2}+(6-3)^{2}  } = \sqrt{6^{2}+3^{2}  } =\sqrt{45}

Given vertices are  B(6,9) and C( 6,-3)

       B C = \sqrt{x_{2}-x_{1} )^{2} +(y_{2}-y_{1} )^{2}  }

             =  \sqrt{(-3-9)^{2}+(6-6)^{2}  } =\sqrt{12^{2} } = 12

    BC = 12

Given vertices are  A(3,3) and C( 6,-3)

 AC = \sqrt{(6-3)^{2}+(-3-3)^{2}  } = \sqrt{9+36} = \sqrt{45}

AC² = AB²+BC²

45  = 45+144

 45  ≠ 189

∴Given Δ ABC is not a right angle triangle

 

5 0
3 years ago
NEED HELP EMERGENCY ‼️
cestrela7 [59]

Answer:

A. Reflect across the y-axis

Step-by-step explanation:

if the negative sign was outside the radical then it would've been a reflection on the x-axis.

6 0
3 years ago
Read 2 more answers
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