Answer:
y = 3/2 x + 3
Step-by-step explanation:
2/3 x + y = -14/3
y = -2/3 x − 14/3
The slope of this line is -2/3. So the perpendicular slope is the opposite of the inverse:
m = -1 / (-2/3)
m = 3/2
We know the slope of the line and a point on the line, so using point-slope form:
y − 0 = 3/2 (x − (-2))
Simplifying into slope-intercept form:
y = 3/2 (x + 2)
y = 3/2 x + 3
Find rates of change until you find a constant.
dy/dx=1,2,3,4,5,6
d2y/dx2=1,1,1,1,1
So the acceleration, d2y/d2x, is constant. This means that this is a quadratic sequence of the form a(n)=an^2+bn+c. So we can set up a system of equations to solve for the values of a,b, and c. Using the first three points, (1,1), (2,2), and (3,4) we have:
9a+3b+c=4, 4a+2b+c=2, and a+b+c=1 getting the differences...
5a+b=2 and 3a+b=1 and getting this difference...
2a=1, so a=1/2 making 5a+b=2 become:
2.5+b=2, so b=-1/2, making a+b+c=1 become:
1/2-1/2+c=1, so c=1 so the rule is:
a(n)=0.5x^2-0.5x+1 or if you prefer to not have decimals
a(n)=(x^2-x+2)/2
1. 35x + 0.15y
=3500x + 15y [multiplying the equation by 100]
= 700x + 3y [dividing the equation by 5]
2. Let x be an even integer
x + (x+2) + (x+2+2)
x+x+2+x+4
3x+6
3. 1/5*(r+7) - 9s
(r+7)/5 - 9s
4. x=cows
y= goats + sheep
x= (y+140)/2
Answer:
The vertex Q' is at (4,5)
Step-by-step explanation:
Given:
Quadrilateral PQRS undergoes a transformation to form a quadrilateral P'Q'R'S' such that the vertex point P(-5,-3) is transformed to P'(5,3).
Vertex point Q(-4,-5)
To find vertex Q'.
Solution:
Form the given transformation occuring the statement in standard form can be given as:
The above transformation signifies the point reflection in the origin.
For the point P, the statement is:
So, for point Q, the transformation would be:
Since two negatives multiply to give a positive, so, we have:
