First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Answer:
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Step-by-step explanation:
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Answer:
7/15 is greater than 5/11
Step-by-step explanation:
7/15= .4667
5/11= .454545
Hope that's helpful
Answer:
1.) 9.2
2.)
625
633
the dealer
8.81
Step-by-step explanation:
I'm gonna assume that cm= compounded monthly
1.)
effective rate: .153/12= .01275
x= payments
2.)
If there is no interest rate attached to financing through the deal the payment is just
37500/60 = 625
The monthly payment from the bank has a present value of 37500-3000=34500
and the effective rate is .039/12= .00325
Finally, the amount we save is just the difference
633.81-625=8.81
Answer:
Step-by-step explanation:
50 dollars = ∉34
∉1 = Rs 150
Rs 382800 / 150 Rs per ∉ = 382800/150 ∉
=2552 ∉
50 dollars = ∉34 so 50/34 dollars = ∉
2552 ∉ × 50/34 dollar per ∉ = in the units the ∉ cancel out
∉ × dollar/∉ = dollars
(2552 × 50) / 34 = 3752.94 dollars <------------------
Here is another way of looking at the answer...........
Rs 382800 × 1∉/150 Rs × 50 dollars/34 ∉ = note how the units cancel
= 382800 × (1/150) × (50/34) Rs × ∉/Rs × dollars/∉
= 3,752.94 dollars leaving only dollars in the numerator
