Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x 
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x 
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
What is 3.1 divided by 10.261Very simple. We have 2 given decimal number in which our dividend which is the 3.1 is lesser than our divisor which is 10.261.Now, let's start the division to be able to find out what is the quotient we're looking.=> 3. 1 / 10.261 = 0.30.Thus, the quotient is o.30, let's check if we got the correct answer.To check simply do the reverse method=> .30 * 10.261 = 3.1<span>
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I can only give possible combination of the ages. Had the sum of the ages been given, then the 3 specific numbers would have been derived.
We need to do prime factorization of 72.
72 ÷ 2 = 36
36 ÷ 2= 18
18 ÷ 2 = 9
9 ÷ 3 = 3
3 ÷ 1 = 1
1 x 2 x 2 x 2 x 3 x 3 = 72
Possible combinations:
1 x 8 x 9 = 72 1 + 8 + 9 = 18
1 x 4 x 18 = 72 1 + 4 + 18 = 23
2 x 4 x 9 = 72 2 + 4 + 9 = 15
3 x 4 x 6 = 72 3 + 4 + 6 = 13
A.
F(10)= (10)^2-3(10)-5
F(10)=100-30-5
F(10)=65
B.
F(-3)=(-3)^2-3(-3)-5
F(-3)=9+9-5
F(-3)=13
C.
G(2)= -6(2)+1
G(2)= -12+1
G(2)=-11
D.
G(10)=-6(10)+1
G(10)= -60+1
G(10)= -59
Answer:
Answer : 3/2
Step-by-step explanation:
30/20= 3/2
it is because we don't want the zero so that we can take it off.
Hope this help you!! :))
