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lawyer [7]
2 years ago
13

Evalúa la expresión 2 (X - 8) cuando X = 12. *​

Mathematics
1 answer:
Jet001 [13]2 years ago
4 0

Answer:

8

Step-by-step explanation:

x = 12

2(x - 8)

2(12 - 8)

2(4)

8

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Explain the difference between solving 2x+15-3x=10 and 2x-4=3x+11
noname [10]
1st one is x=5
2nd one is x=-15
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3 years ago
What is 2/3 – (-2/3)?<br> A. -4/3<br> B. 4/3<br> C. 0<br> D. 2/3<br> Answer is B
kenny6666 [7]

Answer:

answer b

Step-by-step explanation:

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3 years ago
Needed help with a algebra 2 question if so...
erma4kov [3.2K]

Answer:

Quadrant II

Step-by-step explanation:

Since there are 360 degrees in a circle we will subtract it from 860 until we get a number less than 360

860-360=500\\500-360=140

Since it less than 180 but more than 90 it will be in the second quadrant

Hope this helps! <3

5 0
3 years ago
Someone please help me with this algebra problem
nevsk [136]

Answer:

$110

Step-by-step explanation:

We are looking for the decrease in money per desk purchased. Because the x-axis is the number of desks purchased, what we have to find is the (opposite) of the slope. The formula to represent slope can be written as:

\frac{y_{2} -y_{1} }{x_{2}- x_{1} }

We can substitute the points given, (2, 480) and (5, 150) and simplify:

\frac{150-480}{5-2} =\frac{-330}{3} = -110

We would multiply by -1 because we are asking for the decrease, and negative increase is decrease. -1 * -110, gives us $110

4 0
3 years ago
3^x= 3*2^x solve this equation​
kompoz [17]

In the equation

3^x = 3\cdot 2^x

divide both sides by 2^x to get

\dfrac{3^x}{2^x} = 3 \cdot \dfrac{2^x}{2^x} \\\\ \implies \left(\dfrac32\right)^x = 3

Take the base-3/2 logarithm of both sides:

\log_{3/2}\left(\dfrac32\right)^x = \log_{3/2}(3) \\\\ \implies x \log_{3/2}\left(\dfrac 32\right) = \log_{3/2}(3) \\\\ \implies \boxed{x = \log_{3/2}(3)}

Alternatively, you can divide both sides by 3^x:

\dfrac{3^x}{3^x} = \dfrac{3\cdot 2^x}{3^x} \\\\ \implies 1 = 3 \cdot\left(\dfrac23\right)^x \\\\ \implies \left(\dfrac23\right)^x = \dfrac13

Then take the base-2/3 logarith of both sides to get

\log_{2/3}\left(2/3\right)^x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x \log_{2/3}\left(\dfrac23\right) = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(\dfrac13\right) \\\\ \implies x = \log_{2/3}\left(3^{-1}\right) \\\\ \implies \boxed{x = -\log_{2/3}(3)}

(Both answers are equivalent)

8 0
3 years ago
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