Question

How much pure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution

Answer 1

Let's assume

number of teaspoons of pure maple syrup=x

now, we can find maple syrup content of pure syrup

so,

maple syrup content of pure syrup=1.00*x

36 tablespoons of a 45% solution

so,

male syrup content of 45% =45% of 36

male syrup content of 45% $=\frac{45}{100} *36$

male syrup content of 45% $=0.45*36$

so,

total mixture solution =x+36

total maple syrup=60% of (x+36)

and we can also find total maple syrup

total maple syrup =maple syrup content of pure syrup +male syrup content of 45%

total maple syrup $=1.00x+0.45*36$

now, we can set it equal

$0.60(x+36)=1.00x+0.45*36$

now, we can solve for x

$0.60x+0.60*36=1.00x+0.45*36$

$0.60*36-0.45*36=1.00x-0.60x$

$0.40x=0.60*36-0.45*36$

$0.40x=0.15*36$

$x=13.5$

so, 13.5 teaspoons pure maple syrup should be added to 36 tablespoons of a 45% solution in order to obtain a 60% solution..........Answer

Answer 2

(36(0.45) + x)/(x+36) = 0.6,
x + 16.2 = 0.6x + 21.6,
x = 13.5 grams of pure syrup should be added