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PilotLPTM [1.2K]
2 years ago
11

The perimeter of a triangle is 45 centimeters. find the lengths of its sides if the longest side is 7 centimeters longer than th

e first shortest side and the remaining side is 2 centimeters longer than the shortest side
Mathematics
1 answer:
dangina [55]2 years ago
3 0
X = length of shortest side
Therefore the remaining sides will be x +2 and x + 7

x + x + 2 + x +7 = 45
3x + 9 = 45
3x = 36
x = 12
x + 2 = 14
x + 7 = 19

The sides are 12, 14, and 19 cm. long. Hope this helped!
You might be interested in
Kate gave 5/6 of her CDs to Sue. Sue gave 7/8 of these to Joan. Joan gave 3/5 of these to Ann. Ann received 70 CDs how many did
olya-2409 [2.1K]
Let us assume the number of CDs Kate had = x
Number of CDs given to Sue = 5x/6
Number of CDs given to Joan = (5x/6) * ( 7/8)
                                                = 35x/48
Number of CDs given to Ann = (35x/48) * (3/5)
                                              = 7x/16
Total number of CDs Ann received = 70
Then
7x/16 = 70
x = 160
From the above deduction, it can be concluded that the number of CDs that Kate originally had was 160. I hope that this is the answer that has actually come to your help.
5 0
3 years ago
A triangle has side lengths of 6, 8, and 9. what type of triangle is it?
miv72 [106K]
Scalene triangle 
because all sides are of a different length

6 0
2 years ago
5 Divided by (1200+700)
solmaris [256]

Answer:

380

Step-by-step explanation:

1200 + 700 = 1900/5 = 380

7 0
2 years ago
Help with this question ??
NNADVOKAT [17]

Answer: 12 tables minimum, 15 max.

Step-by-step explanation:

If you substitute 14 in an inequality

200c + 500t >= 8800

200(14) + 500t and solve for t, you get t must be at least 12.

C +T cannot exceed 29

So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.

You will have to enter the t values 12,13,14,15

5 0
2 years ago
David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

b^2 = b × b

b^4 =b × b × b × b

GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

7 0
2 years ago
Read 3 more answers
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