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olganol [36]
3 years ago
11

Find two numbers if their difference is 16 and their ratio is 5:7.

Mathematics
2 answers:
lidiya [134]3 years ago
5 0

Answer:

The two numbers are 56 and 40.

Step-by-step explanation:

I don't really know how to explain this but I know that my answer is right.

Sorry.

myrzilka [38]3 years ago
3 0

Let us say that the numbers are x and y. The given clues are:

1. x – y = 16         (so x is the larger number)

2. y / x = 5 / 7

 

rewriting eqtn 2 in terms of y:

y = (5/7) x

 

combining 1 and 2:

x – (5/7) x = 16

(2/7) x = 16

x = 56

 

y = (5/7) x = 40

 

So the two numbers are 56 and 40.

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Alborosie
As it is, in accordance with the priorities of the operators (or the PEMDAS rule) the equation without parentheses mean
<span>(2/3)x+1=(1/6)x-7
I do not suppose you mean the above, since the solution is relatively trivial.

I suppose you actually mean
</span><span>2/(3x+1)=1/(6x-7)
in which case you would cross-multiply:
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and expand/distribute
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Answer:

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