Q: How much did Jay have to pay excluding his share of the insurance premium?
A: $1800+$200 = $2000
Q: How much did Jay's company pay for his insurance premium?
A: $700. If Jay's $350 is 1/3 of the premium , then Jay's company pays 2*$350=$700 as rest of his premium.
Q: Jay paid 10% and the plan paid 90% beyond the deductible. How much did Jay's insurance company pay total?
A: Jay's insurance company paid $16200. Given that Jay paid $1800 beyond his deductible of $200 (and that is 10% of the actual cost) means that his plan (insurance company) paid 90%=9*$1800=$16200.
Q: How much did Jay have to pay total, including his share of the premium?
A: Jay paid $2350. He paid $200 deductible + $1800 beyond deductible + $350 premium
I'm pretty sure 10/63 is simplified.
This histogram is skewed to the left and its distribution's center would be three (3).
<h3>What is a histogram?</h3>
A histogram is used to graphically represent a set of data points into user-specified ranges, especially through the use of rectangular bars.
In this scenario, we can infer the following about the histogram distribution's center, spread, and overall shape:
- This histogram is skewed to the left.
- Its distribution's center would be three (3).
- The spread implies that more students are between 58-59 and 60-61 inches.
- The shape shows that many of the values are at the lower end.
Read more on histogram here: brainly.com/question/21304143
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Answer: Last Option

Step-by-step explanation:
The initial height of the plant of species A is 25 cm and grows 3 centimeters per month.
If m represents the number of months elapsed then the equation for the height of the plant of species A is:

For species B the initial height is 10 cm and it grows 8 cm each month
If m represents the number of months elapsed then the equation for the height of the plant of species B is:

Finally, the system of equations is:

The answer is the last option
I think i only get some of it. this is what i did
x = -3 to 4y = 0.3 to 3if we use -3 and 3a < -1 < b
a= -2 to infiniteb= 0 to infinite