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3 years ago

Find two numbers if their difference is 16 and their ratio is 5:7.

Mathematics

2 answers:

lidiya [134]3 years ago

5 0

Answer:

The two numbers are 56 and 40.

Step-by-step explanation:

I don't really know how to explain this but I know that my answer is right.

Sorry.

myrzilka [38]3 years ago

3 0

Let us say that the numbers are x and y. The given clues are:

1. x – y = 16 (so x is the larger number)

2. y / x = 5 / 7

rewriting eqtn 2 in terms of y:

y = (5/7) x

combining 1 and 2:

x – (5/7) x = 16

(2/7) x = 16

x = 56

y = (5/7) x = 40

So the two numbers are 56 and 40.

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For this, find the value of X for this parallelogram!! Thank you :)

True [87]

Answer:

$\huge\boxed{\sf x = 12 }$

Step-by-step explanation:

Opposite sides and angles of a parallelogram are equal.

So,

3x - 1 = 35

Add 1 to both sides

3x = 35 + 1

3x = 36

Divide 3 to both sides

x = 36 / 3

x = 12

$\rule[225]{225}{2}$

Hope this helped!

7 0

3 years ago

Marty is asked to draw triangles with side lengths of 4 units and 2 units, and a non-included angle of 30°. Select all the trian

777dan777 [17]

Answer:

The drawn in the attached figure

see the explanation

Step-by-step explanation:

<em>First case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\B=30^o$

Applying the law of sines

Find the measure of angle A

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(A)}=\frac{2}{sin(30^o)}$

$sin(A)=1$

$A=90^o$

Find the measure of angle C

In a right triangle

we know that

$B+C=90^o$ ----> by complementary angles

$B=30^o$

therefore

$C=60^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{c}{sin(60^o)}=\frac{2}{sin(30^o)}$

$c=2\sqrt{3}\ units$

therefore

The dimensions of the triangle are

$A=90^o$

$B=30^o$

$C=60^o$

$a=4\ units\\b=2\ units\\c=2\sqrt{3}=3.46\ units$

<em>Second case</em>

In the triangle ABC

Let

$a=4\ units\\b=2/ units\\A=30^o$

Applying the law of sines

Find the measure of angle B

$\frac{a}{sin(A)}=\frac{b}{sin(B)}$

substitute the given values

$\frac{4}{sin(30^o)}=\frac{2}{sin(B)}$

$sin(B)=0.25$

using a calculator

$B=14.48^o$

Find the measure of angle C

we know that

The sum of the interior angles in any triangle must be equal to 180 degrees

$A+B+C=180^o$

$A=30^o\\B=14.48^o$

therefore

$30^o+14.48^o+C=180^o$

$C=135.52^o$

Find the length side c

Applying the law of sines

$\frac{c}{sin(C)}=\frac{a}{sin(A)}$

substitute the given values

$\frac{c}{sin(135.52^o)}=\frac{4}{sin(30^o)}$

$c=5.61\ units$

therefore

The dimensions of the triangle are

$A=30^o$

$B=14.48^o$

$C=135.52^o$

$a=4\ units\\b=2\ units\\c=5.61\ units$

see the attached figure to better understand the problem

4 0

3 years ago

Round 56,477,812 to the nearest hundred thousand,

GrogVix [38]

Answer:

56,500,000.

Step-by-step explanation:

56,477,812 rounded to the nearest hundred thousand:

The 4 is in the hundred thousands place, so we'll look at the next digit to the right of that, which is the 7:

56,<u>4</u>77,812

Since 7 is more than 5, we'll have to go up a number, which will be the 4. Afterwards, we'll have to replace all the digits after the 4 with zeros.

56,500,000.

8 0

3 years ago

In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ. Is this information sufficient to prove triangles DEF a

kenny6666 [7]

In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS

<h3>What are congruent triangles?</h3>

Two triangles are said to be congruent if they have the same shape, all their corresponding angles as well as sides must also be congruent to each other.

Two triangles are congruent using the side - angle - side congruency if two sides and an included angle of one triangle is congruent to that of another triangle.

In triangles DEF and OPQ, ∠D ≅ ∠O, ∠F ≅ ∠Q, and segment DF ≅ segment OQ; this is not sufficient to prove triangles DEF and OPQ congruent through SAS

Find out more on congruent triangle at: brainly.com/question/1675117

#SPJ1

8 0

2 years ago

Earth revolves on its axis once every 24 hours. Which statement are true ? Check all that apply

zhuklara [117]

Answer:

The angular velocity of Earth is π/12 radians per hour.

The angular velocity of Earth is 2π radians per day.

Step-by-step explanation:

A full circumference of a circle (as the Equator line on Earth) is 2π radians.

Since the planet does a full revolution in 24 hours... that means it makes a full turn in a day.

So, we can see that in a day, the planet rotates 360 degrees... or 2π radians per day!

Now, if you want to find the angular velocity per HOUR... you divide that by 24... so 2π/24 = π/12 radians

So, we can also say it does π/12 radians per hour.

3 0

2 years ago