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Elis [28]
3 years ago
14

The sum of the digits of a three-digit number is 6. The hundreds digit is twice the units digit, and the tens digit equals to th

e sum of the other two. Find the number.
Mathematics
1 answer:
wlad13 [49]3 years ago
6 0

Answer:

231

Step-by-step explanation:

231

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Determine if the two lines with the given slope are parallel, perpendicular, or neither. Circle your
Sati [7]

Answer:

As the lines are neither parallel nor perpendicular.

Therefore, the correct answer is ''neither''.

Hence, option C is correct.

Step-by-step explanation:

Given

m₁ = 3/2

m₂ = -3/2

We know that when two lines are parallel, they have equal slopes

But

m₁ ≠ m₂

3/2 ≠ -3/2

As the m₁ and m₂ are not equal.

Hence, the lines are not parallel.

We know that when two lines are perpendicular, the product of their slopes is -1.

Let us check the product of two slopes m₁ and m₂

m₁ × m₂ = 3/2 × -3/2

              = -9/4

              = -2.25

As

m₁ × m₂ ≠ -1

Thus, the lines are not perpendicular.

Conclusion:

As the lines are neither parallel nor perpendicular.

Therefore, the correct answer is ''neither''.

Hence, option C is correct.

8 0
2 years ago
1. Find the value of x.<br> 2. Find the value of y.
DiKsa [7]

Answer:

5y + 85 = 180 \\ 5y = 10 - 85 \\ 95 \div 5 = 19 \\ 5x + 95 = 180 \\ 5x = 180 - 95 \\ 5x = 85 \\ x = 17

5 0
2 years ago
Read 2 more answers
CAN SOMEONE PLEASE HELP ME WITH THIS ILL GIVE YOU BRAINLY IF YOU GET IT RIGHT ALSO PLEASE EXPLAIN HOW YOU GOT THE ANSWER!!!
sesenic [268]

Answer:

C. P(E) = 0.9

Step-by-step explanation:

If E needs to be greater than D, then you have two options. 1.5 and 0.9. Since D is 0.5, I think that the most reasonable answer is 0.9.

[If this is wrong, the you know your answer is B. P(E) = 1.5]

8 0
2 years ago
Dilate the trapezoid using center (-3,4) and scale factor 1/2.
pochemuha

The coordinates of the vertices of the image of the trapezoid are given as;

A'(x, y) = (- 4, 1), B'(x, y) = (- 2, 1), C'(x, y) = (- 5 / 2, 5 / 2) , D'(x, y) = (- 7 / 2, 5 / 2).

<h3>How to find the image of a trapezoid by dilation?</h3>

In this question we have a representation of a trapezoid, whose image has to be generated by a kind of rigid transformation known as dilation, whose equation is described :

P'(x, y) = O(x, y) + k · [P(x, y) - O(x, y)]

Where O(x, y) - Center of dilation

k - Scale factor

And P(x, y) - Coordinates of the original point, P'(x, y) - Coordinates of the resulting point.

Since k = 1 / 2, A(x, y) = (- 5, - 2), B(x, y) = (- 1, - 2), C(x, y) = (- 2, 1), D(x, y) = (- 4, 1), O(x, y) = (- 3, 4),

Therefore, the coordinates of the vertices of the image are:

Point A'

A'(x, y) = O(x, y) + k · [A(x, y) - O(x, y)]

A'(x, y) = (- 3, 4) + (1 / 2) [(- 5, - 2) - (- 3, 4)]

A'(x, y) = (- 3, 4) + (1 / 2)  (- 2, - 6)

A'(x, y) = (- 3, 4) + (- 1, - 3)

A'(x, y) = (- 4, 1)

Point B';

B'(x, y) = O(x, y) + k [B(x, y) - O(x, y)]

B'(x, y) = (- 3, 4) + (1 / 2) [(- 1, - 2) - (- 3, 4)]

B'(x, y) = (- 3, 4) + (1 / 2)  (2, - 6)

B'(x, y) = (- 3, 4) + (1, - 3)

B'(x, y) = (- 2, 1)

Point C';

C'(x, y) = O(x, y) + k · [C(x, y) - O(x, y)]

C'(x, y) = (- 3, 4) + (1 / 2)  [(- 2, 1) - (- 3, 4)]

C'(x, y) = (- 3, 4) + (1 / 2) (1, - 3)

C'(x, y) = (- 3, 4) + (1 / 2, - 3 / 2)

C'(x, y) = (- 5 / 2, 5 / 2)

Point D'

D'(x, y) = O(x, y) + k  [D(x, y) - O(x, y)]

D'(x, y) = (- 3, 4) + (1 / 2) [(- 4, 1) - (- 3, 4)]

D'(x, y) = (- 3, 4) + (1 / 2) (- 1, - 3)

D'(x, y) = (- 3, 4) + (- 1 / 2, - 3 / 2)

D'(x, y) = (- 7 / 2, 5 / 2)

To learn more on dilations:

brainly.com/question/13176891

#SPJ1

3 0
10 months ago
M/n x p for m = 10, n = -5, and p = -2
Novay_Z [31]
M / n x p = 10/-5 x -2 = -2 x -2 = 4
6 0
3 years ago
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