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Luda [366]
2 years ago
6

Help me please number 2 and 3

Mathematics
1 answer:
mixas84 [53]2 years ago
3 0
2)

2*120 + 2*3.14*40 = 240 + 251.2 = 491.2;
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3 years ago
Can you help please I am struggling thank you
Ludmilka [50]

Answer:

m<ADC = 107

Step-by-step explanation:

You need to know three things to solve this problem.

1) Opposite angles of an inscribed quadrilateral are supplementary.

2) The measure of an inscribed angle is half the measure of its subtended arc.

3) The sum of the measures of all the arcs of a circle is 360 deg.

From 1) we get:

m<A + m<C = 180

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m<C = 108

From 2) we get:

m<C = (1/2)m(arc)BAD

108 = (1/2)[m(arc)AB + m(arc)AD]

216 = m(arc)AB + 122

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From 3) we get:

m(arc)AB + m(arc)BC + m(arc)CD + m(arc)DA = 360

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From 2) we get:

m<ADC = (1/2)m(arc)ABC

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m<ADC = 107

3 0
2 years ago
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