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3 years ago

4(3x-2)+6x(2-1) simplified

Mathematics

2 answers:

trasher [3.6K]3 years ago

8 0

The answer : 18x-8

12x-8+6x x1
12x-8+6x

FrozenT [24]3 years ago

6 0

Answer:

The answer is 18x - 8.

Step-by-step explanation: Trust me, an know a lot about math.

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Which is the equation of a hyperbola centered at the origin with vertex (0,sqrt12) that passes through (2sqrt3,6)

GaryK [48]

Answer:

$\frac{y^2}{12}-\frac{x^2}{6}=1$

Step-by-step explanation:

we are given

we can use standard equation of hyperbola

$\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}=1$

where

center=(h,k)

center at origin

so, h=0 and k=0

vertex is

$(0,\sqrt{12})$

we can use formula

vertices: (h, k + a)

we get

$k+a=\sqrt{12}$

we can plug k=0

$a=\sqrt{12}$

now, we can plug these values

$\frac{(y-0)^2}{(\sqrt{12})^2}-\frac{(x-0)^2}{b^2}=1$

now, we are given it passes through $(2\sqrt{3} ,6)$

so, we have

$x=2\sqrt{3},y=6$

we can plug these values and then we can solve for b

$\frac{(6-0)^2}{(\sqrt{12})^2}-\frac{(2\sqrt{3}-0)^2}{b^2}=1$

and we get

$36b^2-144=12b^2$

we can solve for b

and we get

$b=\sqrt{6}$

now, we can plug these values

$\frac{(y-0)^2}{(\sqrt{12})^2}-\frac{(x-0)^2}{(\sqrt{6})^2}=1$

we can simplify it

and we get

$\frac{y^2}{12}-\frac{x^2}{6}=1$

7 0

3 years ago

Read 2 more answers

Does this equation define a linear function y=3/x when x does not equal 0

Fofino [41]

$y= \frac{3}{x}$

no

4 0

3 years ago

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Find the value for the variable that makes the expression undifined.<br> X2 -9<br> X2-7x+10

Anika [276]

an equation is undefined, when its denominator is 0, or turns to 0, because we can't divide anything by 0.

so let's simply set the denominator of this one = 0.

$\bf x^2-7x+10=0\implies (x-2)(x-5)=0\implies x= \begin{cases} 2\\ 5 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(2)^2-9}{(2)^2-7(2)+10}\implies \cfrac{-5}{-10+10}\implies \cfrac{-5}{0}\leftarrow und efined \\\\\\ \cfrac{(5)^2-9}{(5)^2-7(5)+10}\implies \cfrac{16}{-10+10}\implies \cfrac{16}{0}\leftarrow und efined$