Answer:
The height of the prism measures 22 meters
The volume of the prism measures 10,890 cubic meters.
Step-by-step explanation:
The height is twice the width of the prism.
The prism's width is 11 meters.
2 x 11 = 22
The volume of a rectangular prism is calculated as:
V = l x w x h
So, the volume is:
V = 45 x 11 x 22
The volume is 10,890 cubic meters.
Hope this helps!
Answer:
3rd graph down
Step-by-step explanation:
greens are x and carrots are y in my equations
2x - y >= 3
x + 2y < 4
The first equation is solid and will highlight everything to the right of it because it is a >
the second is dashed and will highlight everything to the left of it because it is a <
the only 2 graphs that show this are 1 and 3
looking at the points you can see that the points for the solid line are both the same so ignore those and go to the dashed lined ones.
on the first graph the points are (0,4)
plugging those into our equation gives us 0 + 2*4 <4
or 8<4 which doesnt make sense making 3 the correct graph
(sorry my answer wasnt posting so i had to start over and make it less detailed, but comment if you need any explanation)
Answer:
If it's a rectangle, then point D is (3,-1)
The area would be 7 x 3 = 21 units²
Step-by-step explanation:
Answer:C=15
Step-by-step explanation:
Just do math
Answer:
x ≈ {-11.789, +0.501, 11.288}
Step-by-step explanation:
The cubic g(x) - f(x) = 0 has three real solutions. It can be rewritten as ...
Since the solutions are irrational, they are best found using a spreadsheet or graphing calculator. My favorite graphing calculator shows the approximate solutions below.
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<em>Comment on the problem statement</em>
Your expression for f(x) is ambiguous in that many Brainly questions have the exponentiation indicator replaced by a blank: 3 x -1 often means 3^x -1 and sometimes means 3^(x-1). We have taken the expression at face value and have assumed it is a linear expression. If otherwise, the problem is basically worked the same way: write a function h(x) = g(x) - f(x) and look for solutions to h(x) = 0. Graphing can be useful.
