What is the length of the hypotenus of a right triangle in each of the two legs is 7 units

Mathematics

1 answer:

vlada-n [284]3 years ago

8 0

To find the hypotenuse of a right triangle, use the following formula:

$c=\sqrt{a^2+b^2}$

Your a and your b are your legs. Plug them in. In this case, we plug in 7 for both.

$c=\sqrt{7^2+7^2}$

$c=\sqrt{49+49}$

$c=\sqrt{98}$

Your answer would be:

Approximate: 9.9

Exact: $7\sqrt{2}$

You might be interested in

What is the product?

Sophie [7]

Answer:

Step-by-step explanation:

In exponent multiplication, if base are same just add the powers.

$(-6a^{3}b+2ab^{2})(5a^{2}-2ab^{2}-b)=(-6a^{3}b)*(5a^{2}-2ab^{2}-b)+2ab^{2}*(5a^{2}-2ab^{2}-b)\\\\$

$=(-6a^{3}b)*5a^{2}-(-6a^{3}b)*2ab^{2}-(-6a^{3}b)*b+ 2ab^{2}*5a^{2}-2ab^{2}*2ab^{2}-2ab^{2}*b\\\\=-30a^{3+2}b+12a^{3+1}b^{1+2}+6a^{3}b^{1+1}+10a^{1+2}b^{2}-4a^{1+1}b^{2+2}-2ab^{2+1}\\\\=-30a^{5}b+12a^{4}b^{3}+6a^{3}b^{2}+10a^{3}b^{2}-4a^{2}b^{4}-2ab^{3}\\$