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3 years ago

Factor each expression 8 16 =

1 answer:

8 0

Since they are just next to each other ill take it multiplication and that would be 128 if its not let me know and ill correct it

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If ab = a, then b = A) 0 B) 1 C) a D) even

Zanzabum

Answer:

Step-by-step explanation:

because a number multiplied with 1 is equal to itself

8 0

3 years ago

The distance between Maggie’s home and her school is 5,280 yards. (Hint: 1 mile = 1,760 yards.)

Mariulka [41]

1 mile = 1760 yards
5280 yards = 5280 / 1760 = 3 miles

4 0

3 years ago

Find the value of x.

Otrada [13]

Answer:

the value of x is 29°

hope it helps

have a nice day

5 0

2 years ago

R^3 +4r^2-25r-100 Help

Marina86 [1]

Answer:

The zeroes in this equation are -5, -4, and 5

Step-by-step explanation:

In order to find these, you need to factor by splitting. For this, we separate out the two halves of the equation and pull out the greatest common factor of each. Let's start with the front end.

r^3 + 4r^2

r^2(r + 4)

Now the second half.

-25r - 100

-25(r + 4)

Since what is left in the parenthesis are exactly the same, we can use that parenthesis next to one with what we pulled out.

(r^2 - 25)(r + 4)

And we can further factor the first parenthesis using the difference of two squares

(r^2 - 25)(r + 4)

(r + 5)(r - 5)(r + 4)

Now that we are fully factored, set each parenthesis equal to 0 and solve for x.

r + 5 = 0

r = -5

r - 5 = 0

r = 5

r + 4 = 0

r = -4

7 0

2 years ago

A fish was swimming LaTeX: 2\frac{1}{2}2 1 2 feet below the water's surface at 1:00 p.M. Three hours later, the fish was at a de

marin [14]

Answer:

$\frac{23}{4}$ feet

Step-by-step explanation:

The depth of the fish to the surface of water at 1:00 pm = 2 $\frac{1}{2}$ feet

= $\frac{5}{2}$ feet

The depth of the fish to its initial position at 4:00 pm = 3 $\frac{1}{4}$ feet

= $\frac{13}{4}$ feet

The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm

= $\frac{5}{2}$ + $\frac{13}{4}$

= $\frac{10 + 13}{4}$

= $\frac{23}{4}$

The position of the fish with respect to the water's surface at 4:00 pm is $\frac{23}{4}$ feet.

8 0

2 years ago