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2 years ago

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Mathematics

1 answer:

beks73 [17]2 years ago

4 0

Answer:

y = 8.50x - 6.00

Step-by-step explanation:

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Write a quadratic function f whose zeros are -3 and -4

dlinn [17]

Answer:

Step-by-step explanation:

Zeros α = -3 and β = -4

Quadratic equation: x² - (α + β)x + αβ = 0

x² - (-3-4)x + (-3)*(-4) = 0

x² - (-7)x + 12 =0

x² + 7x + 12 = 0

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3 years ago

1. Deshawn's Bikes rents bikes for $11 plus $5 per hour, Maria paid SSI to rent a bike. For how

marysya [2.9K]

Answer8 hours

Step-by-step explanation:

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3 years ago

Two fourth-degree polynomials are multiplied together. what is the degree of the product?

Snowcat [4.5K]

Answer:

The product of a fourth degree polynomial and a third degree polynomial is a 7th degree polynomial (just add the two degrees). Why is this the case? Remember, when you multiply variables with common bases, you add the exponents. Since the degree of a polynomial is just the largest exponent, you're really just adding the degrees when you multiply

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3 years ago

Find the area of △LKJ.

nirvana33 [79]

Answer:

$A=600\: u^{2}$

<u>The correct answer is letter c.</u>

Step-by-step explanation:

The area equation of a triangle is given by:

$A=\frac{bh}{2}$ (1)

Where:

b is the base

h is the height

Let's find first the angle MJK (α), using the tangent definition.

$tan(\alpha)=\frac{24}{32}$

$\alpha=tan^{-1}(\frac{24}{32})$

$\alpha=36.9^{\circ}$

Now, if α = 37° then β (angle JLK) must be:

$37^{\circ} + \beta + 90^{\circ}=180^{\circ}$

$\beta=53^{\circ}$

Now, we can find the distance ML using again the tangent definition:

$tan(\beta)=\frac{24}{ML}$

$ML=\frac{24}{tan(53)}$

$ML=18$

The base of the triangle LKJ will be:

$b=32+ML=32+18=50$

Therefore, using equation (1) the area of △LKJ will be:

$A=\frac{50*24}{2}$

$A=600\: u^{2}$

The correct answer is c.

I hope it helps you!

5 0

3 years ago

Calcule o valor numérico da expressão a seguir -2/3+1-3/2.8/9

Zolol [24]

Answer:

The calculated value is "0.214"

Step-by-step explanation:

Given expression :

$\bold {\frac{-2}{3}+ 1 -\frac{3}{\frac{2.8}{9}} }\\$

solution:

$\Rightarrow \frac{-2}{3}+ 1 -\frac{3}{\frac{2.8}{9}}\\\\\Rightarrow \frac{-2}{3}+ 1 -\frac{3}{\frac{2.8}{\frac{9}{1}}}\\\\\Rightarrow \frac{-2}{3}+ 1 -\frac{3}{2.8} \times \frac{1}{9}}}\\\\\Rightarrow \frac{-2}{3}+ 1 -\frac{1}{8.4}\\\\\Rightarrow \frac{-16.8 + 25.2- 3}{25.2}\\\\\Rightarrow \frac{5.4}{25.2}\\\\\Rightarrow 0.214$

8 0

3 years ago