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SCORPION-xisa [38]
3 years ago
7

As a salesperson, you are paid $92 per week plus $4 per sale. This week you want your pay to be at least $200. Write an inequali

ty for the number of sales you need to make, and describe the solutions.
Mathematics
2 answers:
sergey [27]3 years ago
7 0

Answer:

92 + 4s ≥ 200; s ≥ 27

Step-by-step explanation:

is the Answer its on USATESTPREP

Debora [2.8K]3 years ago
6 0
4x + 92 ≥ 200 

the $92 are regardless and you make $4 every sale (x) to solve this you would multiply the number of sales (x) by 4 then add the initial 92 
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There are 8 girls for every 7 boys on a field trip.if there 56 girls on the trip how many students are on the trip
Ket [755]

Well the first thing you need to do is set up a proportion.

8 girls         56 girls                          

--------    =   -----------

7 boys             x


Now what we have to do is find out what we multiplied by 8 to get 56.

Simply divide.

56 ÷ 8 = 7

So, we figured out that the magic number is 7!

So we multiply the boy number by 7

7 x 7 = 49

So this means that there are 49 boys on the field trip.

8 0
3 years ago
540 is 10 Times as much as 5,400
Sergio039 [100]
Yes, that is true.....
8 0
3 years ago
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Use the sum of cubes identity to find the factors of the expression 8x6 + 27y3. Write your answer in the form of the expression
Katyanochek1 [597]

The Answer to this Question is:

(2x^2+3y)(4x^4-6x^2y+9y^2)

This symbol ^ means that the number after is an exponent.

5 0
3 years ago
What is the equationof the line that passes through (0,3) and (7,0)
bekas [8.4K]
Answer:

y = - 3/7x + 3

Step-by-step explanation:

First find the slope

Second find the y-intercept (already given by one of the points)

Third write it in slope-intercept form
6 0
2 years ago
The weekly amount spent by a small company for in-state travel has approximately a normal distribution with mean $1450 and stand
Llana [10]

Answer:

0.0903

Step-by-step explanation:

Given that :

The mean = 1450

The standard deviation = 220

sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

P(X > 1560) = P(Z > \dfrac{1560 - 1450}{220})

P(X > 1560) = P(Z > \dfrac{110}{220})

P(X> 1560) = P(Z > 0.5)

P(X> 1560) = 1 - P(Z < 0.5)

From the z tables;

P(X> 1560) = 1 - 0.6915

P(X> 1560) = 0.3085

Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

Then;

Pr ( Y > 20) = P( z > 20)

Pr ( Y > 20) = P(Z > \dfrac{20.5 - 16.042}{3.3306})

Pr ( Y > 20) = P(Z >1 .338)

From z tables

P(Y > 20) \simeq 0.0903

7 0
3 years ago
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