All categories

3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPP

Mathematics

2 answers:

tankabanditka [31]3 years ago

7 0

Answer:

D because mean is the subtraction of the biggest number and the smallest. so 17-8=9

Genrish500 [490]3 years ago

7 0

Answer:

I think it's D

I don't know tho

You might be interested in

Given APQR with vertices P(1,5). Q(-2,1), and R(-4,2), write the translation equivalent to the composition of transformations. L

makvit [3.9K]

Answer Can you explain it a little more

Step-by-step explanation:

3 0

2 years ago

An investment of $900 earns 6% annual interest and is compounded semi-annually. Write an equation

nalin [4]

Answer:

$A=900(1+\frac{0.06}{2})^{2(t)}$

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 6% into a decimal:

6% -> $\frac{6}{100}$ -> 0.06

Since the interest is compounded semi-annually, we will use 2 for n. Lets plug in the values now and your equation will be:

$A=900(1+\frac{0.06}{2})^{2(t)}$

4 0

2 years ago

PLSSS I NEED HELP i will give you 50 points

DIA [1.3K]

Answer:

131.2

Step-by-step explanation:

x/55=31/14

x=31/13*55

x=131.153846154

4 0

3 years ago

An urn contains three red balls and four blue balls. Draw two balls at random from the urn, without replacement. Compute the exp

mezya [45]

Step-by-step explanation:

in total we have 3+4 = 7 balls.

when we draw the first ball, the probability to draw a red ball is 3/7, and a blue ball 4/7.

when we draw the second ball, we have now only 6 balls in total.

the probabilty to draw a red back now depends also on the result of the first draw.

if the first ball was already red, then we have only a chance now of 2 out of 6.

if the first ball was blue, then we have now a chance of 3 out of 6.

so, the probably to draw at least 1 red ball in 2 draws is the probability of drawing one on the first draw plus the probability of drawing one on the second :

1 - probability to see 2 blue balls

1 - 4/7 × 3/6 = 1 - 12/42 = 30/42 = 0.714285714...

the expected number of red balls in 2 draws is

1 red in first red in first red in second

but not second and second but not first

1×(3/7 × 4/6) + 2×(3/7 × 2/6) + 1×(4/7 × 3/6) = 12/42 + 12/42 + 12/42 = 36/42 = 6/7 = 0.857142857 ≈ 0.8571

7 0

2 years ago

10-1: Compound Probability

ahrayia [7]

Answer:

Step-by-step explanation:

Probability of black pens = 3/14

Probability of white paper clips = 16/40

to find the probability of black pen and white paper clip we have to multiply these two probability.

3/14 x 16/40 = 48/560 = 8.6

3 0

3 years ago