I saw this some where before
Answer:
144
Step-by-step explanation:
hope that helps your welcome
tangent is less than 0 or tan(θ) < 0, is another way to say tan(θ) is negative, well, that only happens on the II Quadrant and IV Quadrant, where sine and cosine are different signs, so we know θ is on the II or IV Quadrant.

![\bf \pm\sqrt{3^2-2^2}=a\implies \pm\sqrt{5}=a\implies \stackrel{\textit{II Quadrant}}{-\sqrt{5}=a} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-\sqrt{5}}}{\stackrel{hypotenuse}{3}}~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cpm%5Csqrt%7B3%5E2-2%5E2%7D%3Da%5Cimplies%20%5Cpm%5Csqrt%7B5%7D%3Da%5Cimplies%20%5Cstackrel%7B%5Ctextit%7BII%20Quadrant%7D%7D%7B-%5Csqrt%7B5%7D%3Da%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20~%5Chfill%20cos%28%5Ctheta%20%29%3D%5Ccfrac%7B%5Cstackrel%7Badjacent%7D%7B-%5Csqrt%7B5%7D%7D%7D%7B%5Cstackrel%7Bhypotenuse%7D%7B3%7D%7D~%5Chfill)
Answer:
f(x)=16+ 4x
the constant rate would be 4
Step-by-step explanation:
(2)^2+b2=7^2
4+b2=49
B2=45
Sqrt on both sides
B= sqrt(45)
B=6.7