3 years ago

I need help please!!!!???

Mathematics

1 answer:

marin [14]3 years ago

6 0

Answer:

Yes and you can actually solve it like this:

h + 6 ≥ -2

h ≥ -2 - 6

h ≥ -8

(On the condition that h is greater or equal to -8, the result is always guarantee to be correct)

You might be interested in

How do you rotate the coordinate (9,-6) 270 degrees counterclockwise?

GalinKa [24]

Since this point is located in the fourth quadrant you have to rotate it 270 degrees counterclockwise which would end up being in third quadrant. which means the new point would be (-6,-9)

6 0

3 years ago

PLEASE HELP WILL MARK YOU BRAINLIEST!!! 50 POINTS’

photoshop1234 [79]

Answer:

I can’t answer

Step-by-step explanation:

Pls take a state photo I can’t tell if it is a rectangle or a polygon

6 0

3 years ago

Read 2 more answers

Venla is 5 years older than her cousin Kora. How old is Kora when Venla is 18 years old?

krek1111 [17]

Answer:

kora is 13

Step-by-step explanation:

venla is 5 years older than kora

18-5=13

5 0

3 years ago

Read 2 more answers

a rectangle has an area of 1/6 squar centimeters and a length of 1.5 centimeters what is the width and the perimeter

Alex73 [517]

<span>

(1/6)/ 1.5 =
(1/6)/(15/10)=
1/6*10/15=10/90=1/9 width</span>

3 0

3 years ago

What is the solution to this equation 2/3x+1=1/6×-7

Alika [10]

Answer:

A . x= -16

Step-by-step explanation:

$\\\frac{2}{3}x+1=\frac{1}{6}x-7\\\\\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}\\\\\frac{2}{3}x+1-1=\frac{1}{6}x-7-1\\\\\frac{2}{3}x=\frac{1}{6}x-8\\\\\mathrm{Subtract\:}\frac{1}{6}x\mathrm{\:from\:both\:sides}\\\\\frac{2}{3}x-\frac{1}{6}x=\frac{1}{6}x-8-\frac{1}{6}x\\\\= \frac{1}{2}x=-8\\\\\mathrm{Multiply\:both\:sides\:by\:2}\\\\2\times \frac{1}{2}x=2\left(-8\right)\\\\x=-16$

7 0

3 years ago