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2 years ago

I need help please!!!!???

Mathematics

1 answer:

marin [14]2 years ago

6 0

Answer:

Yes and you can actually solve it like this:

h + 6 ≥ -2

h ≥ -2 - 6

h ≥ -8

(On the condition that h is greater or equal to -8, the result is always guarantee to be correct)

You might be interested in

Human blood has an approximate pH of 7.3. Which substance is more basic than human blood?

ratelena [41]

so, 7 is neutral anything past 7 is considered basic.

answer: a water and ammonia solution with a pH of 11 (very basic).

any number under 7 is acidic and of course there are different degrees of acidic just like there are different degrees of basicity.

______________________________________________________________

- stomach's digestive juices, would be considered very acidic

-apple juice is also acidic but not as acidic like stomach juices.

- grape juice, is becoming less acidic.

________________________________________________________________

Hopefully this helped and good luck.

5 0

2 years ago

Yesterday, James sold $29 worth of cookies and chocolate at his store. He sells cookies for $5 a box, and chocolate for $2 a bar

MAXImum [283]

Answer:

he sold 4 boxes of cookies and 3 chocolate bars

Step-by-step explanation:

5+5+5+5 = 20 3+3+3 = 9 so add 20+9 = 29

8 0

2 years ago

The patio is rectangular and has a total area of 24 square feet.you are building a rectangular fish and want the length of the p

prohojiy [21]

The answer is 2x * 5y + 15= 21.21

8 0

3 years ago

Jan and Wayne went to the store to buy some groceries. Jan bought 2 cans of corn beef hash and 3 cans of creamed chipped beef fo

yulyashka [42]

Answer:

The system of equations that models the problem is:

$\left \{ {{2*H+3*C=4.95} \atop {3*H+2*C=5.45}} \right.$

Step-by-step explanation:

A system of equations is a set of two or more equations with several unknowns in which we want to find a common solution. So, a system of linear equations is a set of (linear) equations that have more than one unknown that appear in several of the equations. The equations relate these variables or unknowns to each other.

In this case, the unknown variables are:

H: price of a can of corn beef hash
C: price of a can of creamed chipped beef

Knowing the unit price of a product, the price of a certain quantity of that product is calculated by multiplying that quantity by the unit price. So the price for 2 cans of ground beef hash can be calculated as 2 * H and the price for 3 cans of ground beef with cream can be calculated as 3 * C. Jan paid $ 4.95 for those amounts from both cans. This means that the sum of the can prices must be $ 4.95. So: 2*H + 3*C= 4.95 Equation (A)

Thinking similarly, if Wayne bought 3 cans of corn beef hash and 2 cans of creamed chipped beef for $5.45, Wayne's buy can be expressed by the equation:

3*H + 2*C= 5.45 Equation (B)

Finally, the system of equations that models the problem is:

$\left \{ {{2*H+3*C=4.95} \atop {3*H+2*C=5.45}} \right.$

7 0

2 years ago

I need to know how to do the answer and why that’s the anwer

Pavel [41]

Ok so the answer is
$4 {x}^{2}$

so we multiply numbers that have the same variable

$2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\$
multiply 2 x 2

$2 \times 2 = 4$
then multiply the exponents

$x ^{3} \times x ^{ - 1}$
multipling like this will look like addition.
${x}^{3} \times {x}^{ - 1} = {x}^{2}$
so in other words you could do it like this too
${x}^{3} + {x}^{ - 1} = {x}^{2}$
now add the exponent with 4
$4 + {x}^{2} = 4x ^{2}$

now for the last part
${y}^{3} + {y}^{ - 3} = 0$
because -3 and 3 added together make 0
$0 + 4 {x}^{2} = 4 {x}^{2}$
I hope this help(it looks complicated but it's very easy and I hope I helped you out)

6 0

2 years ago