The coordinates of the vertices of AJKL are J(-5, -1), K(0, 1), and L(2, -5).
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Using the normal distribution, it is found that the two readings that are cutoff values separating the rejected thermometers from the others are -1.96ºC and 1.96ºC.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
.
The z-score that cuts off the bottom and top 2.5% of the distribution is , hence:
X = -1.96
X = 1.96
The two readings that are cutoff values separating the rejected thermometers from the others are -1.96ºC and 1.96ºC.
More can be learned about the normal distribution at brainly.com/question/27879230
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Answer:
see the attachment for the graph
Step-by-step explanation:
Since all you want is the graph, it is convenient to use a graphing program to produce it.
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You will notice that the point on the circle is 4 units over and 3 units up from the center.* This tells you the square of the radius is 4²+3² = 25. You only need to know this if you're using a graphing calculator to plot the equation ...
(x +4)^2 +(y -1)^2 = 25
If you're graphing this by hand, you can set your compass to the distance between the plotted points, as we have done in our graphing program.
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* Hopefully, you recognize these (4 and 3) as the legs of a 3-4-5 right triangle, so you know immediately that the radius is 5. Even if you don't, you can figure it using the Pythagorean theorem, as we have done above.
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The standard form equation of a circle with center (h, k) and radius r is ...
(x -h)^2 +(y -k)^2 = r^2
