Question

The coordinates of the vertices of AJKL are J(-5, -1), K(0, 1), and L(2, -5).

Answer 1

We need slope of all lines ?

• J(-5,-1)
• K(0,1)
• L(2,-5)

Slope of JK:-

$\\ \sf\longmapsto m=\dfrac{1+1}{0+5}=\dfrac{2}{5}$

Slope of KL:-

$\\ \sf\longmapsto m=\dfrac{-5-1}{2-0}=\dfrac{-6}{0}=-3$

Slope of JL

$\\ \sf\longmapsto m=\dfrac{-5-1}{2+5}=\dfrac{-6}{7}$