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Novosadov [1.4K]
2 years ago
12

The coordinates of the vertices of AJKL are J(-5, -1), K(0, 1), and L(2, -5).

Mathematics
1 answer:
dalvyx [7]2 years ago
7 0

We need slope of all lines ?

  • J(-5,-1)
  • K(0,1)
  • L(2,-5)

Slope of JK:-

\\ \sf\longmapsto m=\dfrac{1+1}{0+5}=\dfrac{2}{5}

Slope of KL:-

\\ \sf\longmapsto m=\dfrac{-5-1}{2-0}=\dfrac{-6}{0}=-3

Slope of JL

\\ \sf\longmapsto m=\dfrac{-5-1}{2+5}=\dfrac{-6}{7}

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inn [45]

Answer:

The constant in the expression is 12

Step-by-step explanation:

The constant of the expression is the value that is independent of the number of minutes Janelle uses. The expression can  be written as :

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f(2= = 0.05*2 +12 =0.1 +12 = 12.1

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The second graph.

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3 years ago
Let u = &lt;-3, -5&gt;, v = &lt;-3, 1&gt;. Find u + v. &lt;-2, -8&gt; &lt;-8, -2&gt; &lt;0, -6&gt; &lt;-6, -4&gt;
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