The MOST precise measurements this ruler can give are to the nearest

Mathematics

1 answer:

Ann [662]3 years ago

7 0

Answer:

D) Sixteenth inch

Step-by-step explanation:

Because it is the smallest.

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What is the probability of the spinner landing on an odd number?

Arada [10]

Answer:

1/2

Step-by-step explanation:

If there are 4 numbers 1 and 3 are odd numbers and 2 and 4 are even numbers. Therefore half of the numbers are odd.

Hope this helps

Please mark me as Brainliest

5 0

3 years ago

Consider the following theorem. Theorem If f is integrable on [a, b], then b a f(x) dx = lim n→[infinity] n i = 1 f(xi)Δx where

mel-nik [20]

Split up the interval [1, 9] into n subintervals of equal length (9 - 1)/n = 8/n :

[1, 1 + 8/n], [1 + 8/n, 1 + 16/n], [1 + 16/n, 1 + 24/n], …, [1 + 8 (n - 1)/n, 9]

It should be clear that the left endpoint of each subinterval make up an arithmetic sequence, so that the i-th subinterval has left endpoint

1 + 8/n (i - 1)

Then we approximate the definite integral by the sum of the areas of n rectangles with length 8/n and height $f(x_i)$ :

$\displaystyle \int_1^9 (x^2-4x+6) \,\mathrm dx \approx \sum_{i=1}^n \frac8n\left(\left(1+\frac8n(i-1)\right)^2-4\left(1+\frac8n(i-1)\right)+6\right)$

Take the limit as n approaches infinity and the approximation becomes exact. So we have

$\displaystyle \int_1^9 (x^2-4x+6) \,\mathrm dx = \lim_{n\to\infty} \sum_{i=1}^n \frac8n\left(\left(1+\frac8n(i-1)\right)^2-4\left(1+\frac8n(i-1)\right)+6\right) \\\\ = \lim_{n\to\infty} \frac8n \sum_{i=1}^n \left(1+\frac{16}n(i-1)+\frac{64}{n^2}(i-1)^2-4-\frac{32}n(i-1)+6\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \sum_{i=1}^n \left(64(i-1)^2-16n(i-1)+3n^2\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \sum_{i=0}^{n-1} \left(64i^2-16ni+3n^2\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(64\sum_{i=0}^{n-1}i^2 - 16n\sum_{i=0}^{n-1}i + 3n^2\sum{i=0}^{n-1}1\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(\frac{64(2n-1)n(n-1)}{6} - \frac{16n^2(n-1)}{2} + 3n^3\right) \\\\= \lim_{n\to\infty} \frac8{n^3} \left(\frac{49n^3}3-24n^2+\frac{32n}3\right) \\\\= \lim_{n\to\infty} \frac{8\left(49n^2-72n+32\right)}{3n^2} = \boxed{\frac{392}3}$

3 0

3 years ago

Plsssss helppp meeeeee

denis-greek [22]

Answer:

First choice, 1/3

Step-by-step explanation:

If you look at 1 to A to B to 2, you would see that there are 3 gaps between them. Therefore it's out of three, A to B is only one gap distance so it's 1/3

7 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (5,7) and (-1, 19) ?

Alexandra [31]

For this case we have that by definition, having two points through which a line passes $(x_ {1}, y_ {1})\ and\ (x_ {2}, y_ {2})$ , we can find its slope of the following form: