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3 years ago

What is the image of (2, 1) after a reflection over the x-axis?

Mathematics

1 answer:

astra-53 [7]3 years ago

3 0

Answer:

(2, -1)

Step-by-step explanation:

Whenever you reflect a point over the x-axis, the x-coordinate remains the same, but the y-coordinate becomes its additive inverse.

(x, y) ⇒ (x, -y).

(2, 1) ⇒ (2, -1).

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(X^3+1)dividend (x-1)

bazaltina [42]

$x^3=x\cdot x^2$ and $x^2(x-1)=x^3-x^2$ . So we have a remainder of

$(x^3+1)-(x^3-x^2)=x^2+1$

$x^2=x\cdot x$ and $x(x-1)=x^2-x$ . Subtracting this from the previous remainder gives a new remainder

$(x^2+1)-(x^2-x)=x+1$

$x=x\cdot1$ and $1(x-1)=x-1$ . Subtracting this from the previous remainder gives a new one of

$(x+1)-(x-1)=2$

and we're done since 2 does not divide $x$ . So we have

$\dfrac{x^3+1}{x-1}=x^2+x+1+\dfrac2{x-1}$

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3 years ago

Verify the identity. Show your work. (1 + tan^2u)(1 - sin^2u) = 1

yuradex [85]

$\bf \textit{Pythagorean Identities}
\\\\
sin^2(\theta)+cos^2(\theta)=1\implies cos^2(\theta)=1-sin^2(\theta)
\\\\ 1+tan^2(\theta)=sec^2(\theta)\\\\
-------------------------------\\\\\
[1+tan^2(u)][1-sin^2(u)]=1
\\\\\\\
[sec^2(u)][cos^2(u)]\implies \cfrac{1}{cos^2(u)}\cdot cos^2(u)\implies \cfrac{cos^2(u)}{cos^2(u)}\implies 1$

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3 years ago

Find the greatest common factor of 24, 64, 108.

Ainat [17]

Answer:

The answer is 4.

Step-by-step explanation:

To find the greatest common factor (GCF), start by listing the factors of each number.

For 24: 1, 2, 3, 4, 6, 8, 12, 24

For 64: 1, 2, 4, 8, 16, 32, 64

For 108: 1, 2, 3, 4, 6, 9, 12, 18

Since all the factors are now written out, we can find the greatest common factor between 24, 64, and 108, and the GCF is 4.

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3 years ago

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Yuliya22 [10]

Answer:

Y || Z

Step-by-step explanation:

We know that Y⊥B, and Z⊥B, which means both Y and Z are perpendicular to B, meaning that they both create 90° angles with B, and from that, we can make the conclusion that Y || Z

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4 years ago

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What is the surface area of a piece of pipe that is open at both ends, has a radius of 6 inches, and a height of 18 inches? (Use

Ratling [72]

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3 years ago