15·x²=15·x so
x²=x
x·x=x with x≠0 than x must be 1
x=1
Answer:
Multiply by 3 on both sides of the equation.
2.78 × 3 = 8.34, so t = 8.34.
Substitute 8.34 for t to check the solution.
Step-by-step explanation:
To solve the equation = 2.78
we will use the steps below to solve this equation;
First, multiply by 3 on both-side of the equation. That is;
× 3= 2.78 × 3
On the left hand side of the equation 3 will cancel-out 3, leaving us with just t while 3 will be multiply by 2.77 on the right-hand side of the equation to give 8.34
t = 8.34
we can further substitute 8.34 for t to check the correctness of the solution
that is;
= 2.78
R
An equation without exponents and two variables, is typically a straight line. All the points on the line with integer coordinates are solutions of the equation. Since x and y have to be positive as well, there aren't that many solutions.
Let's see where the line crosses the x-axis, it is where y=0:
x/0.5 + 0 = 18, so x=9 at the intercept. y=0 there, so this is a point on the line, but not a solution to the question (y was supposed to be positive).
Possible values for x are thus limited to 1,2,3,4,5,6 and 7. You can try them all (ie., solve the equation with them) and see for which x values the y is also positive and integer.
You will find that x=4, y=2 is the only pair that satisfies these conditions.
Answer:
32
Step-by-step explanation:
24 divided by 6 is 4. 4 times 8 is 32