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2 years ago

2 A change in the genes of a species over a long period of time.

2 answers:

7 0

This is a very vague question. there are several correct answers including development, mutations, divergence, etc.
be more specific.

Blizzard [7]2 years ago

3 0

Answer:

There is no question..?

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In a survey, four out of five people surveyed preferred creamy over chunky peanut butter. 120 people are shopping at the grocery

elixir [45]

Answer: Around 96 people would prefer creamy peanut butter.

Step-by-step explanation:

In the survey was found that 4 out of 5 preferred creamy over chunky peanut butter.

Then the relative frequency is:

4/5 = 0.8 prefer creamy peanut butter.

And we can assume that:

1/5 = 0.2 prefer chunky peanut butter.

We also could multiply these numbers by 100% to obtain the percentage forms:

0.8*100% = 80%

0.2*100% = 20%

Now, if there are 120 people in the grocery store, we can expect that the 80% will prefer creamy peanut butter.

Then we can expect that the number of people that prefers creamy peanut butter is:

N = (80%/100%)*120 = 0.8*120 = 96

Around 96 people would prefer creamy peanut butter.

3 0

2 years ago

What is the least common denominator of the fractions 2/3 and 3/5? HELP PLEASE

grigory [225]

Answer:what is the least common denominator of the fractions 2/3 and 3/5? HELP PLEASE

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

How would I solve this i got 4.5

Aliun [14]

Answer:

$up \: is \: the \: angle \: bisector \\ so \: 54 = 5x - 6 \\ 5x = 54 + 6 \\ 5x = 60 \\ x = \frac{60}{5} = 12 \\ thank \: you$

6 0

2 years ago

Read 2 more answers

Please help me solve this... I will mark you brainliest if it’s correct

Crank

(5 + 7x + 6)/2 = 3x + 9

7x + 11 = 6x + 18

7x - 6x = 7

x = 7

EF = 3x + 9

= 3(7) + 9

= 21 + 9

= 30

8 0

2 years ago

The owner of a bike shop that produces custom built bike frames has determined that the demand equation for bike frames is given

o-na [289]

Answer:

equilibrium point (10,340)

Step-by-step explanation:

To find the equilibrium point, equal the demand and the supply:

$D(q)=S(q)\\\\-6.10q^2-5q+1000=3.2q^2+10q-80$

Reorganize the terms in one side and reduce similar terms:

$3.2q^2+6.1q^2+5q+10q-80-1000=0\\\\9.3q^2+15q-1080=0$

that's a cuadratic equation, solve with the general formula when:

a=9.3, b=15, c=-1080

$q_{1}=\frac{-b+\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{1}=\frac{-15+\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{1}=\frac{-15+201}{18.6}\\\\q_{1}=\frac{186}{18.6}\\\\q_1=10$

q can't be negative because it is the quantity of bike frames, so:

$q_{2}=\frac{-b-\sqrt{b^{2}-4ac} }{2a}\\\\q_{2}=\frac{-15-\sqrt{(-15)^{2}-4(9.3)(-1080)} }{2(9.3)}\\\\q_{2}=\frac{-15-201}{18.6}\\\\q_{2}=\frac{-216}{18.6}\\\\$

This value of q can't be considered.

Then substitute the value of q in D(q) to find the price p:

$D(10) = -6.10(10)^2-5(10) + 1000\\\\D(10)=340=p$

The equilibrium point (q,p) is (10,340).

6 0

3 years ago