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Sophie [7]
3 years ago
13

Find the distance between 2 and -2.

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0

Answer:

4

Step-by-step explanation:

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Solve the system by graphing. It is REQUIRED to check your solution. Show work for this problem on your work page.
Hunter-Best [27]

Answer:

y=x-1

y=-2x-4

although I cant summon a graph for this one, I can give cords

for first graph (-2,-3),(-1,-2),(0,-1), (1,0),(2,1)

For second graph the slope is down 2 over 1, and begins at (0,-4).

(-2,0)(-1,-2),(0,-4),(1,-6),(2,-8)

6 0
3 years ago
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Is –0.45 – 0.6 + 0.75p equal to –3(0.15 – 0.2 + 0.25p)
polet [3.4K]

Answer:

no, the have a negative difference

3 0
3 years ago
Judi is making a frame for a square painting. The square painting is 11 3/8 inches on each side. To make sure that she has enoug
dimulka [17.4K]

Answer:

53\frac{1}{2}\ in

Step-by-step explanation:

we know that

The perimeter of a square is equal to

P=4a

where

a is the length side of the square

in this problem we have

a=11\frac{3}{8}\ in

convert to an improper fraction

11\frac{3}{8}\ in=\frac{11*8+3}{8}=\frac{91}{8}\ in

Find the perimeter of the square

P=4\frac{91}{8}=45.5\ in

Remember to adds two extra inches for each corner

so

The wood needed is  

45.5\ in+2*4\ in= 53.5\ in

convert to mixed number

53.5\ in=53\frac{1}{2}\ in

5 0
3 years ago
Why would a railway be important to either side in the civil war?
GaryK [48]

Answer:

Either side would have been improved by a railway so they could get more ammo in and get food in and also get the sick and wonded out to get medical attention

Step-by-step explanation:

7 0
3 years ago
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You have decided to wallpaper your rectangular bedroom. The dimensions are 12 feet 6 inches by 10 feet 6 inches by 8 feet 0 inch
Schach [20]

Answer:

Number of wallpaper needed = At/Aw = 355.3/75

N = 4.74 ~= 5 rolls

Step-by-step explanation:

Given;

Length of the room = 12 feet 6 inches = 12.5 ft

Breadth of the room = 10 feet 6 inches= 10.5ft

Height of the room = 8 feet

Window = 4 ft by 3ft

door = 7ft by 3 ft

Wall paper = 30 inches by 30ft = 2.5ft by 30ft

The total area of the walls of the room is;

Area = Area of the four walls - Area of the two windows and a door.

A = 2LH + 2BH - Area of windows and door

A = 2(12.5×8) + 2(10.5×8) - 2(4×3) -(7×3)

A = 323ft^2

Allowing 10% waste, total area of wallpaper needed is;

At = 323 × 1.10 = 355.3ft^2

Area of wallpaper Aw= 2.5×30 = 75ft^2

Number of wallpaper needed = At/Aw = 355.3/75

N = 4.74 ~= 5 rolls

3 0
3 years ago
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