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photoshop1234 [79]
3 years ago
13

What is the correct way to show a repeating decimal for the fraction ?

Mathematics
1 answer:
Luda [366]3 years ago
4 0

A decimal number with a digit (or group of digits) that repeats forever. The part that repeats can also be shown by placing dots over the first and last digits of the repeating pattern, or by a line over the pattern. Also called a "Repeating Decimal".

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HELP!!!!!!!!!!!!!!!!!!!!!HELP ME PLEASE I WILL GIVE YOU 50 ponts
LiRa [457]

Answer:

D

Step-by-step explanation:

-3/8 converted to a decimal is -0.375

The absolute value of -0.5 is 0.5

hence, 0.5 is larger than -0.375

so the answer is d

hope this helps and is right :)

6 0
3 years ago
Read 2 more answers
A rental agency charges a fee of 6% of month's rent for finding an apartment. Nikolai is looking at apartments with monthly rent
DIA [1.3K]
Since $880 is the cheapest apt., we will use that one. The. 880 + 6%= $932.80
4 0
4 years ago
I need help on ratios
Klio2033 [76]

Answer:

-help

Step-by-step explanation:

A ratio compares values. A ratio says how much of one thing there is compared to another thing. A ratio indicates how many times one number contains another.

example:  there are 6 girls to 4 boys. (6:4)

4 0
3 years ago
(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul
Aloiza [94]

Answer

(a) F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

Step-by-step explanation:

(a) f(t) = 20.5 + 10t + t^2 + δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 f(s)e^{-st} \, dt

where a = ∞

=>  F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt

where d(t) = δ(t)

=> F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt

Integrating, we have:

=> F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3}  )\left \{ {{a} \atop {0}} \right.

Inputting the boundary conditions t = a = ∞, t = 0:

F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}

(b) f(t) = e^{-t} + 4e^{-4t} + te^{-3t}

The Laplace transform of function f(t) is given as:

F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt

F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt

F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt

Integrating, we have:

F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.

Inputting the boundary condition, t = a = ∞, t = 0:

F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}

3 0
3 years ago
Solve for x.
Rasek [7]
A and E

The absolute value of 2+x must equal 8 once we subtract 1 from each side.

This means 2+x can equal -8 or 8. If it is -8, x will equal -10, and if it is 8, x will equal 6.
8 0
3 years ago
Read 2 more answers
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