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Inessa [10]
4 years ago
14

Can the mean value theorum be applied to the function f(x)=1/x^2 on the interval [-2, 1]? Explain.

Mathematics
1 answer:
Temka [501]4 years ago
7 0

Answer:

No, it can not be applied.

Step-by-step explanation:

f(x) = 1/x²

f(x) is a polynomial that is not continuous

As,

f(x) = 1/0 is undefines

Secondly, it is not differentiable (i.e. the derivative does not exists on the interval given)

Derivative of this function

f'(x) = (1)x^-2

       = -2x^(-2-1)

       = -2x^(-3)

       = -2/x³

      =  -2/x³

f'(0) = -2/0 is undefined

Thus, mean value theorem can not be applied.

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The rectangle has a perimeter p of 58 inches. the length l is one more than 3 times the width w. write and solve a system of lin
pogonyaev
P = 2(L + W)
P = 58
L = 3W + 1

58 = 2(3W + 1 + W)
58 = 2(4W + 1)
58 = 8W + 2
58 - 2 = 8W
56 = 8W
56/8 = W
7 = W <=== width is 7 inches

L = 3W + 1
L = 3(7) + 1
L = 21 + 1
L = 22 <=== length is 22 inches

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3 years ago
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Answer:

They are two angles that have a common vertex and a common side.

Step-by-step explanation:


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Step-by-step explanation:

This is the best answer because you recieve the most money. 2630*12 is 31560 dollars, and 665*52= $34580.

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4 years ago
How to solve number 1?
Archy [21]
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3)\ H(x)=9x^2-(2x+1)^2\\\\a.\ H(x)=(3x)^2-(2x+1)^2=[3x-(2x+1)](3x+2x+1)\\=(3x-2x-1)(5x+1)=(5x+1)(x-1)\\\\b.\ H(x)=0\\\\(5x+1)(x-1)=0\iff5x+1=0\ \vee\ x-1=0\\5x=-1\ \vee\ x=1\\\boxed{x=-0.2\ \vee\ x=1}
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3 years ago
Please help me Im so confused right now
tresset_1 [31]

Answer:

The car is traveling 475200 feet per hour. That means in 2 seconds it will have gone 264 feet.

Step-by-step explanation:

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