3 years ago

Sin4θ - sin2θ = _____ 2cos3θcosθ 2cos3θsinθ 2sin3θcosθ 2sin3θsinθ

Mathematics

1 answer:

DIA [1.3K]3 years ago

5 0

Answer:

B. 2cos3θsinθ.

Step-by-step explanation:

Use the identity

sin x - sin y = 2 [cos(x + y)/2]sin [x - y)/2].

So we have:

sin4θ - sin2θ = 2 cos (4θ+2θ)/2 sin (4θ-2θ)/2

= 2cos3θsinθ.

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