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SVEN [57.7K]
3 years ago
12

Sin4θ - sin2θ = _____ 2cos3θcosθ 2cos3θsinθ 2sin3θcosθ 2sin3θsinθ

Mathematics
1 answer:
DIA [1.3K]3 years ago
5 0

Answer:

B.  2cos3θsinθ.

Step-by-step explanation:

Use the identity

sin x - sin y   = 2 [cos(x + y)/2]sin [x - y)/2].

So we have:

sin4θ - sin2θ = 2 cos (4θ+2θ)/2 sin (4θ-2θ)/2

= 2cos3θsinθ.

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