All categories

3 years ago

Can anyone solve this problem and show work

Mathematics

1 answer:

arsen [322]3 years ago

8 0

Check the solution of all options

First option
p + 2 1/2 = 5
p = 5 - 2 1/2
p = 5 - 5/2
p = 10/2 - 5/2
p = 5/2
p = 2 1/2

Second option
2 + p = 2 1/2
p = 2 1/2 - 2
p = 1/2

Third option
p - 2 1/2 = 5
p = 5 + 2 1/2
p = 7 1/2

Fourth option
4 - p = 2 1/2
-p = 2 1/2 - 4
-p = 5/2 - 4
-p = 5/2 - 8/2
-p = -3/2
p = 3/2
p = 1 1/2

The equation that has p = 2 1/2 as its solution is first option

You might be interested in

Giving brainliest!!!!!! If you don’t know the answer please don’t answer it

antoniya [11.8K]

Answer:

The answer is D)

4 0

3 years ago

Read 2 more answers

Question 1 (1 point)

schepotkina [342]

Answer:

a is the perimeter which is given as 820 mm.

Step-by-step explanation:

Perimeter, P = 820 mm

Length is 100 m less than twice of width

let the length is x and the width is y.

So,

x = 2 y - 100

P = 2 (x + y)

820 = 2 (2y - 100 + y)

410 = 3 y - 100

3 y = 510

y = 170 mm

x = 2 x 170 - 100 = 240 mm

The equation is

2 x = 2 y = a

where, a is the perimeter which is given as 820 mm.

8 0

4 years ago

Tamara and Jason work at a widget factory. Tamara arrived at work before Jason and began making widgets. Tamara had already made

Mrac [35]

Answer:

See explanation!

Step-by-step explanation:

The remaining question reads:

Part A: Write a system of equations to represent the situation. Let x = hours and y = widgets.

Part B: How much time does it take for Tamara and Jason to produce the same number of widgets?

Part C: How many widgets will Tamara and Jason have produced?

-------------------------------------------------------------------------------------------------------------

To solve this problem we can construct an linear algebraic expression for each person, principally denoted as:

$y=ax+c$

where

$y$ :is our dependent variable (which is a function of $x$ )

$x$ :is our independent variable

$a$ :is the slope

$c$ :is the y-intercept constant value (if any present)

Part A: Write a system of equations to represent the situation. Let x = hours and y = widgets.

Tamara

Has already made 20 widgets and produces at a rate of 8 widgets per hour thus here $c=20$ and $a=8$ , so Tamara's equation reads:

$y_{T}=8x+20$

Jason

Has not produced any widgets yet and produces at a rate of 12 widgets per hour thus here $c=0$ and $a=12$ , so Jason's equation reads:

$y_{J}=12x$

So the system of equations will be

$y_{T}=8x+20\\y_{J}=12x$

Part B: How much time does it take for Tamara and Jason to produce the same number of widgets?

Since we want to find the amount of time (i.e. the value of $x$ ) it takes for both of them to produce the same number of widgets we can just equate the two equations ans solve for $x$ as follow:

$y_{T}=y_{J}\\8x+20=12x\\8x-12x=-20\\-4x=-20\\x=\frac{-20}{-4}\\ x=5$