How do you solve 8(c-9)=6(2c-12)-4c

1 answer:

4 0

$8(c-9)=6(2c-12)-4c\ \ \ \ | omiting\ the\ brackets\\\\
8c-72=12c-72-4c\ \ \ \ | addition\ of\ similar\ numbers\\\\
8c-72=8c-72\\\\
0=0\\\\There\ are\ infinitely\ many\ solutions.$

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