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Nesterboy [21]
3 years ago
13

A news anchorman can read 7.5 lines in 0.5 minutes. How many lines can he read in 8.5 minutes? Round the answer to the nearest t

enth, if necessary.
A. 15.0 lines B. 127.5 lines
C. 31.9 lines D. 2.7 lines
Mathematics
1 answer:
VashaNatasha [74]3 years ago
7 0
The answer is 127.5 Lines.
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Simplify to create an equivalent expression. 8−4(−x+5) Choose 1 answer: A 4x−12 B −4x−12 C 4x+13 D 4x+5
Kaylis [27]

Answer:

A (4x-12)

Step-by-step explanation:

Still think of PEMDAS: 8-4(-x=5)

a) Multiply -4(-x + 5)

* -4(-x) = 4x (remember a neg x neg = pos)

* -4(5) = - 20

b) Now it reads = 8 +4x - 20

c) put all like terms together

* 8 - 20 = -12

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3 years ago
Can someone help me with credit recovery
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Answer:

Credit recovery is a term used to describe a wide variety of educational strategies and programs that give high school students who have failed a class the opportunity to redo coursework or retake a course through alternate means—and thereby avoid failure and earn academic credit.

Step-by-step explanation:

I'm not sure if this help but if it does good luck with it.

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2 years ago
90 - 15 x 12 divided 6 Plz help! I’ll give some points!
PilotLPTM [1.2K]
I believe it’s 900. Yeah, I think the answer is 900.
3 0
3 years ago
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Jensen Tire & Auto is in the process of deciding whether to purchase a maintenance contract for its new computer wheel align
sasho [114]

Answer:

Step-by-step explanation:

Hello!

The given data corresponds to the variables

Y:  Annual Maintenance  Expense ($100s)

X: Weekly Usage  (hours)

n= 10

∑X= 253; ∑X²= 7347; \frac{}{X}= ∑X/n= 253/10= 25.3 Hours

∑Y= 346.50; ∑Y²= 13010.75; \frac{}{Y}= ∑Y/n= 346.50/10= 34.65 $100s

∑XY= 9668.5

a)

To estimate the slope and y-intercept you have to apply the following formulas:

b= \frac{sumXY-\frac{(sumX)(sumY)}{n} }{sumX^2-\frac{(sumX)^2}{n} } = \frac{9668.5-\frac{253*346.5}{10} }{7347-\frac{(253)^2}{10} }= 0.95

a= \frac{}{Y} -b\frac{}{X} = 34.65-0.95*25.3= 10.53

^Y= a + bX

^Y= 10.53 + 0.95X

b)

H₀: β = 0

H₁: β ≠ 0

α:0.05

F= \frac{MS_{Reg}}{MS_{Error}} ~~F_{Df_{Reg}; Df_{Error}}

F= 47.62

p-value: 0.0001

To decide using the p-value you have to compare it against the level of significance:

If p-value ≤ α, reject the null hypothesis.

If p-value > α, do not reject the null hypothesis.

The decision is to reject the null hypothesis.

At a 5% significance level you can conclude that the average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

b= 0.95 $100s/hours is the variation of the estimated average annual maintenance expense of the computer wheel alignment and balancing machine is modified when the weekly usage increases one hour.

a= 10.53 $ 100s is the value of the average annual maintenance expense of the computer wheel alignment and balancing machine when the weekly usage is zero.

c)

The value that determines the % of the variability of the dependent variable that is explained by the response variable is the coefficient of determination. You can calculate it manually using the formula:

R^2 = \frac{b^2[sumX^2-\frac{(sumX)^2}{n} ]}{[sumY^2-\frac{(sumY)^2}{n} ]} = \frac{0.95^2[7347-\frac{(253)^2}{10} ]}{[13010.75-\frac{(346.50)^2}{10} ]} = 0.86

This means that 86% of the variability of the annual maintenance expense of the computer wheel alignment and balancing machine is explained by the weekly usage under the estimated model ^Y= 10.53 + 0.95X

d)

Without usage, you'd expect the annual maintenance expense to be $1053

If used 100 hours weekly the expected maintenance expense will be 10.53+0.95*100= 105.53 $100s⇒ $10553

If used 1000 hours weekly the expected maintenance expense will be $96053

It is recommendable to purchase the contract only if the weekly usage of the computer is greater than 100 hours weekly.

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2 years ago
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Sedbober [7]

Answer

You deposit $800 in an account that earns 7.5% annual interest compounded quarterly.

Step-by-step explanation:

From the close eye, this seems to me the best and most factual answer to be found!! Goodluck with your quiz!

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