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xenn [34]
3 years ago
8

Compute the permutations and combinations. 10C10 10 0 1

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

wait plse

o

Step-by-step explanation:

i know the answere i am quite busy will answer u later

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Look at the picture please help
Ahat [919]

Answer

3,120

5 times 5 because the two lines make it positive then subtract 15,625 and then divide everything by neg. 5

8 0
3 years ago
Read 2 more answers
Helpppppppppppppppppppppppppppppp
3241004551 [841]
Answer:

first option: Harulo is correct because the angle is coterminal with 3π / 4 and the reference angle is π / 4.

Explanation:

1) 19 π/4 = 4π + 3 π/4, which is 4 complete turns and 3/4 of turn.

2) 3 π/4 is in the third quadrant, so the reference angle is π - 3 π/4 = π/4

3) sin (π/4) = sin (3π/4) = (√2) / 2

4) csc (π/4) =  1 / [ sin (3π/4) ] = 1 / [ (√2) / 2 ] = 2 / (√2) = √2, which shows the validity of the statement and csc(19π/4) = √2.
3 0
3 years ago
Please help.<br> Its a True or False question.
faust18 [17]

Answer:

1. False

2. True

3. True

Step-by-step explanation:

Remark

The point of this question is to encourage you to make use of your calculator. Every calculator can find square roots as far as I know.

Givens

\sqrt{70} = 8.367

\sqrt{72} = 8.49

\sqrt{77} = 8.77

One

Point A is roughly 8.15. The square root of 70 is over 8.3 So square root 70 is to the right of point A. False.

Two

Square root 72 is 8.49. B is 8.3 and C is 8.6. The statement is True

Three

sqrt(77) = 8.77. Point D is 8.75.  The answer is true, but I wouldn't want to bet money on it. The difference is slightly less than 2 100s.

4 0
3 years ago
Read 2 more answers
2y+3x² +5+y+2x+x²+2 what are the coefficients?
saw5 [17]

Answer: 200

The quadratic function f(x) = a(x - h)2 + k, a not equal to zero, is said to be in standard form. If a is positive, the graph opens upward, and if a is negative, then it opens downward. The line of symmetry is the vertical line x = h, and the vertex is the point (h,k).

Any quadratic function can be rewritten in standard form by completing the square. (See the section on solving equations algebraically to review completing the square.) The steps that we use in this section for completing the square will look a little different, because our chief goal here is not solving an equation.

Note that when a quadratic function is in standard form it is also easy to find its zeros by the square root principle.

Example 3.

Write the function f(x) = x2 - 6x + 7 in standard form. Sketch the graph of f and find its zeros and vertex.

f(x) = x2 - 6x + 7.

= (x2 - 6x )+ 7.        Group the x2 and x terms and then complete the square on these terms.

= (x2 - 6x + 9 - 9) + 7.

We need to add 9 because it is the square of one half the coefficient of x, (-6/2)2 = 9. When we were solving an equation we simply added 9 to both sides of the equation. In this setting we add and subtract 9 so that we do not change the function.

= (x2 - 6x + 9) - 9 + 7. We see that x2 - 6x + 9 is a perfect square, namely (x - 3)2.

f(x) = (x - 3)2 - 2. This is standard form.

From this result, one easily finds the vertex of the graph of f is (3, -2).

To find the zeros of f, we set f equal to 0 and solve for x.

(x - 3)2 - 2 = 0.

(x - 3)2 = 2.

(x - 3) = ± sqrt(2).

x = 3 ± sqrt(2).

To sketch the graph of f we shift the graph of y = x2 three units to the right and two units down.

If the coefficient of x2 is not 1, then we must factor this coefficient from the x2 and x terms before proceeding.

Example 4.

Write f(x) = -2x2 + 2x + 3 in standard form and find the vertex of the graph of f.

f(x) = -2x2 + 2x + 3.

= (-2x2 + 2x) + 3.

= -2(x2 - x) + 3.

= -2(x2 - x + 1/4 - 1/4) + 3.

We add and subtract 1/4, because (-1/2)2 = 1/4, and -1 is the coefficient of x.

= -2(x2 - x + 1/4) -2(-1/4) + 3.

Note that everything in the parentheses is multiplied by -2, so when we remove -1/4 from the parentheses, we must multiply it by -2.

= -2(x - 1/2)2 + 1/2 + 3.

= -2(x - 1/2)2 + 7/2.

The vertex is the point (1/2, 7/2). Since the graph opens downward (-2 < 0), the vertex is the highest point on the graph.

Exercise 2:

Write f(x) = 3x2 + 12x + 8 in standard form. Sketch the graph of f ,find its vertex, and find the zeros of f. Answer

Alternate method of finding the vertex

In some cases completing the square is not the easiest way to find the vertex of a parabola. If the graph of a quadratic function has two x-intercepts, then the line of symmetry is the vertical line through the midpoint of the x-intercepts.

The x-intercepts of the graph above are at -5 and 3. The line of symmetry goes through -1, which is the average of -5 and 3. (-5 + 3)/2 = -2/2 = -1. Once we know that the line of symmetry is x = -1, then we know the first coordinate of the vertex is -1. The second coordinate of the vertex can be found by evaluating the function at x = -1.

Example 5.

Find the vertex of the graph of f(x) = (x + 9)(x - 5).

Since the formula for f is factored, it is easy to find the zeros: -9 and 5.

The average of the zeros is (-9 + 5)/2 = -4/2 = -2. So, the line of symmetry is x = -2 and the first coordinate of the vertex is -2.

The second coordinate of the vertex is f(-2) = (-2 + 9)(-2 - 5) = 7*(-7) = -49.

Therefore, the vertex of the graph of f is (-2, -49).

8 0
2 years ago
What value should be added to the expression to create a perfect square?
Lilit [14]
Answer is D.Don't take out the square

8 0
3 years ago
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