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3 years ago

8

Compute the permutations and combinations. 10C10 10 0 1

1 answer:

kozerog [31]3 years ago

8 0

Answer:

wait plse

o

Step-by-step explanation:

i know the answere i am quite busy will answer u later

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Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

2 years ago

Which data set has a median of 15?

Neporo4naja [7]

Answer: The last one is the one with the Median

Step-by-step explanation: Hope this helps ^^

6 0

2 years ago

Read 2 more answers

Question 2 help pls

KengaRu [80]

X=-2
5-4=1
so whatever is square rooted must be equal to 1
1 squared is 1
-2+3 is one

7 0

2 years ago

Read 2 more answers

Solve r=s/17−t for t

mamaluj [8]

T=-r+s/17

Explanation:

6 0

2 years ago

Hi. Please I need help with these questions.

ElenaW [278]

Answer:

Q 12 roots of the equation

$2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\$

∝ = $\frac{\sqrt{10} }{2}$

β = $-\frac{\sqrt{10} }{2}$

no matter if u oppose the root

(i) 2( $\frac{\sqrt{10} }{2}$ ) $(-\frac{\sqrt{10} }{2} )^{2}$ +2 $(\frac{\sqrt{10} }{2} )^{2}$ ( $-\frac{\sqrt{10} }{2}$ )+2(

(ii)( $(\frac{\sqrt{10} }{2})^{2}$ - 3 ( $\frac{\sqrt{10} }{2}$ )( $-\frac{\sqrt{10} }{2}$ ) + ( $(-\frac{\sqrt{10} }{2})^{2}$ ) = $\frac{25}{2}$

Q 13 roots of equation

$4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443$

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

$x^{2}-\frac{1}{4} x-\frac{1}{9}$

4 0

3 years ago