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Aloiza [94]
4 years ago
7

Write the linear equation in slope intercept form 2x+By=16

Mathematics
1 answer:
allochka39001 [22]4 years ago
3 0

Answer:

Part 1) y=-\frac{2x}{B}x+\frac{16}{B}

Part 2) y=-\frac{1}{4}x+2

Step-by-step explanation:

Part 1)

we know that

The equation of the line in slope intercept form is equal to

y=mx+b

we have

2x+By=16

Isolate the variable y

subtract 2x both sides

By=-2x+16

Divide by B both sides

y=-\frac{2x}{B}x+\frac{16}{B}

Part 2)

we know that

The equation of the line in slope intercept form is equal to

y=mx+b

we have

2x+8y=16

Isolate the variable y

subtract 2x both sides

8y=-2x+16

Divide by 8 both sides

y=-\frac{2x}{8}x+\frac{16}{8}

Simplify

y=-\frac{1}{4}x+2

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4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

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What is limit of (x cubed 3 x squared 4 x minus 12) as x approaches negative 3? –78 –24 30 54
Sergio039 [100]

The limit of the expression as x approaches -3 is -24

<h3>How to determine the limit of the expression?</h3>

The expression is given as:

x^3 + 3x^2 + 4x - 12

As x approaches -3.

The limit expression becomes

\lim_{x \to -3} x^3 + 3x^2 + 4x - 12

Substitute -3 for x in the expression

\lim_{x \to -3} (-3)^3 + 3(-3)^2 - 4*3 - 12

Evaluate the expression

\lim_{x \to -3} -24

Hence, the limit of the expression as x approaches -3 is -24

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Answer:

C

Step-by-step explanation:

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