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adoni [48]
2 years ago
5

What is limit of (x cubed 3 x squared 4 x minus 12) as x approaches negative 3? –78 –24 30 54

Mathematics
1 answer:
Sergio039 [100]2 years ago
7 0

The limit of the expression as x approaches -3 is -24

<h3>How to determine the limit of the expression?</h3>

The expression is given as:

x^3 + 3x^2 + 4x - 12

As x approaches -3.

The limit expression becomes

\lim_{x \to -3} x^3 + 3x^2 + 4x - 12

Substitute -3 for x in the expression

\lim_{x \to -3} (-3)^3 + 3(-3)^2 - 4*3 - 12

Evaluate the expression

\lim_{x \to -3} -24

Hence, the limit of the expression as x approaches -3 is -24

Read more about limit expressions at:

brainly.com/question/16176002

#SPJ4

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On a coordinate plane, a line goes through (0, negative 1) and (3, 1). a point is at (negative 3, 0). what is the equation of th
Vitek1552 [10]

Required Equation is y = \frac{2x}{3}+2

Given: A line passing through ({x}_1,{y}_1) and ({x}_2,{y}_2)

Slope = \frac{(y_2 - y_1)}{(x_2 - x_1)} = \frac{( 1 - (-1))}{(3 - 0)}= \frac{2}{3}

Equation of line is:

Y_1(x) = \frac{2}{3}x + b

Where b is y intercept

for value of b

Y_1(0) = -1 = \frac{2}{3}*0 + b = b

⇒ b = -1

and Equation of line is:

Y_1(x) = \frac{2}{3}x + (-1)

For another parallel line that passes through the point (-3,0)

Y_2(x)= \frac{2}{3}x + c

Y_2(-3) = 0 = {2}{3}*-3 + c = -2 + c = 0

c = 2

then the equation is:

Y_2(x) = \frac{2}{3}x + 2

To learn more, visit:

brainly.com/question/14013431

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5 0
2 years ago
Why does he look so off
victus00 [196]
He’s a cocain addict. They snort them Poland bro
8 0
2 years ago
Read 2 more answers
Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sampl
lidiya [134]

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13

x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88

x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63

x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38

x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13

So, the table becomes:

\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}

Next, calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}

\bar x = \frac{1845.73}{146}

\bar x = 12.64

Next, the sample variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}

\sigma^2 = \frac{2393.6875}{145}

\sigma^2 = 16.51

The sample standard deviation is:

\sigma = \sqrt{\sigma^2}

\sigma = \sqrt{16.51}

\sigma = 4.06

6 0
3 years ago
My homework says, "Does the graph represent a proportional relationship? Why or why not? You MUST explain to get credit."
VMariaS [17]

Answer:

No, the graph does not represent a proportional relationship. It is a straight line, but it does not intersect the point (0, 0). ... It's not proportional because the line does not cross through the origin. Therefore the ratio of x to y will be different for two different points on the line.

4 0
3 years ago
In January Jennifer was allowed to use 150 text messages. If she is allowed to use the same amount of text messages every month.
Firlakuza [10]

She would have used 1200 messages in all by the month of August.

Step-by-step explanation:

Messages allowed per month = 150

There will be 8 months starting from January to August, therefore,

Time period = 8 months

Messages in 8 months = Messages per month * Time period

Messages\ in\ 8\ months=150*8\\Messages\ in\ 8\ months=1200

She would have used 1200 messages in all by the month of August.

Keywords: Multiplication

Learn more about multiplication at:

  • brainly.com/question/629998
  • brainly.com/question/6208262

#LearnwithBrainly

6 0
3 years ago
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