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Ad libitum [116K]
3 years ago
12

(c + 3) - 2c - (1 - 3c) = 2 what is this answer to this problem?

Mathematics
1 answer:
Eddi Din [679]3 years ago
6 0
(c+3)-2c-(1-3c)=2
c+3-2c-1+3c=2
2c+2=2
2c=0
c=0
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Can someone help pls
Arlecino [84]

Answer:

I think it may be D

Step-by-step explanation:

A coefficient is the number being multiplied by the variable. A variable is a letter that holds an number like  w x 7=?  W=6. And a constant is the number by itself. In this expression 5000 is the constant 20 is the coefficient and teh variable is w so I think it is D

5 0
2 years ago
If A || B and B | y, then ?
aniked [119]

Answere: I believe that the answere is C.

Step-by-step explanation:

Well,since the lines A and B are paralel and the line y is not paralel with any of then y and A are not paralel.Plus there is not a line called x in this particular equazion.If you have any questions , please contact me.

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8 0
3 years ago
What are the coordinates of the point?
Olenka [21]

Answer:

(-3,6)

Step-by-step explanation:

As  graph shows x=-3 and y=6  

6 0
3 years ago
Read 2 more answers
Equivalent answers for 64 to the power of 2/3
madreJ [45]

Answer:

16

Step-by-step explanation:

Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:

64^\frac{2}{3} = \sqrt[3]{64^{2}}\\

As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.

64^\frac{x}{y} = \sqrt[y]{64^{x}}

Both the original problem (64^2/3) and the converted formula can be put into a calculator.

<u>Simplify (if you want to)</u>

<u />\sqrt[3]{64^{2}}\\\sqrt[3]{4096}\\16<u />

<u />

64 to the power of 2/3 is 16.

5 0
3 years ago
When playing the roulette at a casino, you have exactly 1/35 chance of winning in each round if you play a single number. Your f
Vikentia [17]

Answer:

0.2275 = 22.75% probability that you actually won that round

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Fireworks going off

Event B: You won

Probability of fireworks going off.

100% of 1/35 = 0.0286(when you win)

10% of 34/35 = 0.9714(you lost). So

P(A) = 0.0286 + 0.1*0.9714 = 0.12574

Probability of you winning and fireworks going off:

100% of 1/35, so P(A \cap B) = 0.0286

If you failed to see the outcome of a round, but you see the fireworks going off, then what is the probability that you actually won that round?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0286}{0.12574} = 0.2275

0.2275 = 22.75% probability that you actually won that round

8 0
3 years ago
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