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mars1129 [50]
3 years ago
5

(See Image Attachment) Please explain how you got the answer. Thanks.

Mathematics
1 answer:
sveticcg [70]3 years ago
7 0
So when a problem asks for distance per meter you know there has to be a fraction involved. So you would put 6 over the fraction 3/8. So simplest form would be to just simplify the fraction. To simplify, you would multiply 8 by the top and bottom which gives you 48/3 minutes per meter. Dividing this gives you the answer 16 minutes per meter. Hope that helps.
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Is the following relation a function?<br><br><br> x y<br> 1 4<br> −1 −2<br> 3 10<br> 5 16
Sergio [31]
No , because it doesn’t have a pattern . For example put the numbers in a chart 1+3 = 4 , -1+3 =2 , 3+7=10 , 5+11=16 , there’s no pattern
3 0
3 years ago
The graph of a quadratic function contains (4,-64) and it's vertex is at the origin.write an equation for this function.
lesya692 [45]

Answer:

Step-by-step explanation:

Not sure what form you need this in, but it really doesn't matter, as you'll see in the final equation.  I used the vertex form and solved for a:

y=a(x-h)^2+k

We are given the vertex (h, k) as the origin (0, 0), and we have a point that the graph goes through as (4, -64).  That's our x and y.  Plugging in what we have:

-64=a(4-0)^2+0 gives us

-64 = 16a and

a = -4.  That means that the quadratic equation is

y=-4x^2  which is both vertex form and standard form here, no difference.

5 0
3 years ago
In a cohort of 35 graduating students, there are three different prizes to be awarded. If no student can receive more than one p
sweet [91]

We have been given in a cohort of 35 graduating students, there are three different prizes to be awarded. We are asked that in how many different ways could the prizes be awarded, if no student can receive more than one prize.

To solve this problem we will use permutations.

_{r}^{n}\textrm{P}={_{3}^{35}\textrm{P}}

We know that formula for permutations is given as

_{r}^{n}\textrm{P}=\frac{n!}{(n-r)!}

On substituting the given values in the formula we get,

{_{3}^{35}\textrm{P}}=\frac{35!}{(35-3)!}=\frac{35!}{32!}

=\frac{35\cdot 34\cdot 33\cdot 32!}{32!}\\&#10;\\&#10;=35\cdot 34\cdot 33=39270

Therefore, there are 39270 ways in which prizes can be awarded.


6 0
3 years ago
What two equivalent ratios for 30 to 6
alexgriva [62]
Two equivalent ratios for 30 to 6 can be 15 to 3 or 45 to 9
5 0
3 years ago
Please help someone..
snow_tiger [21]

Answer:  \bold{\dfrac{1}{5}}

<u>Step-by-step explanation:</u>

\dfrac{DF}{AK}=\dfrac{4}{20}=\large\boxed{\dfrac{1}{5}}

4 0
3 years ago
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