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The number of applicants is 20.
a).The number of ways 20 applicants can be split into two jobs is a question of combination as arrangment is not a necessity in this problem.
b).The number of ways in which 20 applicant can be split into these two jobs categories can be determined as,
Thus, there will be 21 ways in which the jobs can be split into these two categories.
Answer:
a) 
b) 16.81%
Step-by-step explanation:
a)
The general formula for compound growth is:

Where
F is the future amount (5000 in our case)
P is the present amount (10 here)
r is the rate of growth (we don't know that yet)
t is the time in years (that would be 1980 - 1940 = 40)
So, the formula becomes:

b)
We need to find the growth rate (annual percentage increase). So we have to solve for "r" in the equation found in part (a).
![500=(1+r)^{40}\\\sqrt[40]{500} =\sqrt[40]{(1+r)^{40}} \\1.1681=1+r\\r = 1.1681 - 1 = 0.1681](https://tex.z-dn.net/?f=500%3D%281%2Br%29%5E%7B40%7D%5C%5C%5Csqrt%5B40%5D%7B500%7D%20%3D%5Csqrt%5B40%5D%7B%281%2Br%29%5E%7B40%7D%7D%20%5C%5C1.1681%3D1%2Br%5C%5Cr%20%3D%201.1681%20-%201%20%3D%200.1681)
To get percentage, we multiply by 100:
0.1681 * 100 = 16.81%
Answer:
what?
Step-by-step explanation:
Answer:
T10= -21
Step-by-step explanation:
If Sn=n^2+3 then t10=?
Sn= n²+5
put n=1, 2
S1= T1 = (1)²+5
=1+5 =6
S2= n²+5
S2=(2)²+5
S2=4+5
S2=9
T2 = S2 - S1
T2 = 9-6
T2=3
T10 = a+(n-1)d
where a = 6, d = -3, n=10
T10= 6+(10-1)*-3
T10=6+(9)*-3
T10=6+(-27)
T10=6-27
T10= -21
Therefore T10= -21 ....