With continuous data, it is possible to find the midpoint of any two distinct values. For instance, if h = height of tree, then its possible to find the middle height of h = 10 and h = 7 (which in this case is h = 8.5)
On the other hand, discrete data can't be treated the same way (eg: if n = number of people, then there is no midpoint between n = 3 and n = 4).
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With that in mind, we have the following answers
1) Continuous data. Time values are always continuous. Any two distinct time values can be averaged to find the midpoint
2) Continuous data. Like time values, temperatures can be averaged as well.
3) Discrete data. Place locations in a race or competition are finite and we can't have midpoints. We can't have a midpoint between 9th and 10th place for instance.
4) Continuous data. We can find the midpoint and it makes sense to do so when it comes to speeds.
5) Discrete data. This is a finite number and countable. We cannot have 20.5 freshman for instance.
The domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).
<h3>What are domain and range?</h3>
The domain means all the possible values of the x and the range means all the possible values of the y.
The function is given below.
y = 3/(x + 8)
Then the domain of the function is (-∞, -8) and (-8, ∞). Then the range of the function will be (-∞, 0) and (0, ∞).
More about the domain and range link is given below.
brainly.com/question/12208715
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Answer:
The answer is B
Step-by-step explanation:
You have to add the 480 dollars which eliminates A and C. Then, when finding commission you make the commission rate into decimal form which eliminates D. Your only option left is B
“Times as fast” means you need to multiply the original speed (10^11) by how many times faster the faster processor works:
10^11 instructions/second • 10^3 faster = 10^14 instructions/second
The key is “___ times as fast”.
Answer:
5n+8
Step-by-step explanation:
We are swamped with questions today so i will not be able to provide you with work. But I'm a college professor. Trust my answer.
Glad I was able to help!!
