Answer:
The perimeter and area of the square are 56 units and 196 square units, respectively.
Step-by-step explanation:
The inner right triangle represents a 45-45-90 right triangle, which has the feature of a hypotenuse whose length is time the length of any of its legs. If the hypotenuse has a measure of , then the legs of the triangle have a measure of .
Now, we are aware that the side length of the square is twice the length of the leg of the right triangle. Then, side length of the square is 14 units long.
Lastly, we know from Geometry that the perimeter and area of the square are represented by the following expressions:
Perimeter
(1)
Area
(2)
Where is the side length of the square.
If we know that , then the perimeter and area of the square are, respectively:
The perimeter and area of the square are 56 units and 196 square units, respectively.
Answer:
The slope of a linear function. The steepness of a hill is called a slope. The same goes for the steepness of a line. The slope is defined as the ratio of the vertical change between two points, the rise, to the horizontal change between the same two points, the run.
Step-by-step explanation:
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Answer:
8/3 km
Step-by-step explanation:
we can represent the given information on a table:
Kilometers time (hours)
2/5 ⇔ 1 1/2
and since we want to know how many kilometers (x) will be paved on 10 hours:
Kilometers time (hours)
2/5 ⇔ 1 1/2
x ⇔ 10
The relationship these 3 numbers have can be described by using the <u>rule of three,</u> which is to multiply the cross quantities on the table (2/5 by 10) and then divide by the remaining amount (1 1/2):
x = ÷
x = ÷
we use
x = ÷
and we make the division:
x = ÷ =
we simplify the fraction by dividing the numerator and denominator both by 5, and we get the result:
x =
thus, in 10 hours the crew will pave 8/3 km. Which is about 2.66 km.
Green's theorem<span> is what falls out of </span>Stokes<span>' </span>theorem if you restrict it to two dimensions.<span>Stokes’ theorem is a generalization of both of these: given some orientable manifold of an arbitrary dimension, it relates integrals over the boundary of a manifold to integrals over its interior.</span>